实际上,我正在使用 jQuery mobile 开发一个 phonegap android 应用程序,其中我设计了一个页面,该页面将退出模拟器和设备屏幕。请帮助我搜索但不了解如何将其保留在手机的范围内。
<!DOCTYPE html>
<html>
<head>
<title>Page Title</title>
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet"
href="http://code.jquery.com/mobile/1.3.0/jquery.mobile-1.3.0.min.css" />
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script
src="http://code.jquery.com/mobile/1.3.0/jquery.mobile-1.3.0.min.js"></script>
</head>
<body>
<div data-role="page" id="device1">
<div data-role="header" style="text-align: center;">Message one</div>
<div data-role="content">
<table width="100%" cellpadding="5" cellspacing="0" border="0">
<tr>
<td align="left">InfodeepIndians</td>
<td align="right" colspan="2">3 Minutes ago</td>
</tr>
<tr>
<td colspan="3" align="justify">Samsung pioneered the trend of
a new breed of devices, now more commonly known as
'phablets',smartphones that are (almost) nearing tablets in size.</td>
</tr>
<tr>
<td align="left">By panel.</td>
<td align="center">21.12%</td>
<td align="right">21 / 30</td>
</tr>
<tr>
<td align="left" col><input type=text></td>
<td align="center"><input type=text></td>
<td align="right"><input type=text></td>
</tr>
<tr>
<td align="left" col><input type=button value="Nos Limit"></td>
<td align="center"><input type=button value="% delivery"></td>
<td align="right"><input type="button" value="% match"></td>
</tr>
</table>
</div>
<div data-role="footer" style="text-align: center;">@Copyrights</div>
</div>
</body>
</html>