我用scrapy做一个废品,我在django上的模型是:
class Creative(models.Model):
name = models.CharField(max_length=200)
picture = models.CharField(max_length=200, null = True)
class Project(models.Model):
title = models.CharField(max_length=200)
description = models.CharField(max_length=500, null = True)
creative = models.ForeignKey(Creative)
class Image(models.Model):
url = models.CharField(max_length=500)
project = models.ForeignKey(Project)
还有我的scrapy模型:
from scrapy.contrib.djangoitem import DjangoItem
from app.models import Project, Creative
class ProjectItems(DjangoItem):
django_model = Project
class CreativeItems(DjangoItem):
django_model = Creative
所以当我保存时:
creative["name"] = hxs.select('//*[@id="owner"]/text()').extract()[0]
picture = hxs.select('//*[@id="owner-icon"]/a/img/@src').extract()
if len(picture)>0:
creative["picture"] = picture[0]
creative.save()
# Extract title and description of the project
project["title"] = hxs.select('//*[@id="project-title"]/text()').extract()[0]
description = hxs.select('//*[@class="project-description"]/text()').extract()
if len(description)>0:
project["description"] = description[0]
project["creative"] = creative
project.save()
我得到了错误:
Project.creative”必须是“Creative”实例。
那么,我怎样才能在scrapy上添加一个外键值呢?