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嗨，我一直在尝试从我的 C# 代码将数据发布到 PHP webservice（第 3 方）。PHP web 服务说它需要一个参数c（缺少参数c是我得到的错误）。我正在使用 JSON 发送数据，但我不明白如何提供参数。如果有人能对此有所了解，那就太好了。以下是我的代码：

DropYa d = new DropYa();
List<DropYaUser> d1 = new List<DropYaUser>();
DropYaUser ds = new DropYaUser();
ds.action = "create";
ds.groupid = 10;
ds.name = "Test";
ds.manager_key = "test";
d1.Add(ds);

WebRequest request = WebRequest.Create(" http://dev.dropya.net/api/Group.php");
// Set the Method property of the request to POST.
request.Method = "POST";
// Create POST data and convert it to a byte array.
JavaScriptSerializer ser = new JavaScriptSerializer();//typeof(DropYaUser));

string postData = ser.Serialize(ds);
byte[] byteArray = Encoding.UTF8.GetBytes(postData);
// Set the ContentType property of the WebRequest.
request.ContentType = "application/json";

// Set the ContentLength property of the WebRequest.
request.ContentLength = byteArray.Length;
// Get the request stream.

Stream dataStream = request.GetRequestStream();
// Write the data to the request stream.
dataStream.Write(byteArray, 0, byteArray.Length);
// Close the Stream object.
dataStream.Close();
Console.Write("Wrote");
Console.Read();
// Get the response.
WebResponse response = request.GetResponse();
// Display the status.
Console.WriteLine(((HttpWebResponse)response).StatusDescription);
// Get the stream containing content returned by the server.
Console.Read();

dataStream = response.GetResponseStream();
Console.Read();
// Open the stream using a StreamReader for easy access.
StreamReader reader = new StreamReader(dataStream);
// Read the content.
string responseFromServer = reader.ReadToEnd();
// Display the content.
Console.WriteLine(responseFromServer);
// Clean up the streams.
reader.Close();
dataStream.Close();
Console.Read();
response.Close();
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1 回答 1

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任何发布请求都将作为数据流读取。已发布表单的字段名称和值将以“c=ABC&d=123”之类的形式出现在流中，其中“c”和“d”是表单字段。当然，您可以在没有任何表单字段名称的情况下发布，但在这种情况下，它需要“c”。您想要做的是在您发布的数据前面加上“c=”。也许像这样修改您的 GetBytes 行：

byte[] byteArray = Encoding.UTF8.GetBytes("c=" + postData);
于 2013-02-22T05:37:16.453 回答