27

使用gensim我能够从 LSA 中的一组文档中提取主题,但是如何访问从 LDA 模型生成的主题?

打印lda.print_topics(10)代码时出现以下错误,因为print_topics()返回 a NoneType

Traceback (most recent call last):
  File "/home/alvas/workspace/XLINGTOP/xlingtop.py", line 93, in <module>
    for top in lda.print_topics(2):
TypeError: 'NoneType' object is not iterable

编码:

from gensim import corpora, models, similarities
from gensim.models import hdpmodel, ldamodel
from itertools import izip

documents = ["Human machine interface for lab abc computer applications",
              "A survey of user opinion of computer system response time",
              "The EPS user interface management system",
              "System and human system engineering testing of EPS",
              "Relation of user perceived response time to error measurement",
              "The generation of random binary unordered trees",
              "The intersection graph of paths in trees",
              "Graph minors IV Widths of trees and well quasi ordering",
              "Graph minors A survey"]

# remove common words and tokenize
stoplist = set('for a of the and to in'.split())
texts = [[word for word in document.lower().split() if word not in stoplist]
         for document in documents]

# remove words that appear only once
all_tokens = sum(texts, [])
tokens_once = set(word for word in set(all_tokens) if all_tokens.count(word) == 1)
texts = [[word for word in text if word not in tokens_once]
         for text in texts]

dictionary = corpora.Dictionary(texts)
corpus = [dictionary.doc2bow(text) for text in texts]

# I can print out the topics for LSA
lsi = models.LsiModel(corpus_tfidf, id2word=dictionary, num_topics=2)
corpus_lsi = lsi[corpus]

for l,t in izip(corpus_lsi,corpus):
  print l,"#",t
print
for top in lsi.print_topics(2):
  print top

# I can print out the documents and which is the most probable topics for each doc.
lda = ldamodel.LdaModel(corpus, id2word=dictionary, num_topics=50)
corpus_lda = lda[corpus]

for l,t in izip(corpus_lda,corpus):
  print l,"#",t
print

# But I am unable to print out the topics, how should i do it?
for top in lda.print_topics(10):
  print top
4

10 回答 10

21

经过一番折腾,似乎print_topics(numoftopics)ldamodel一些错误。所以我的解决方法是使用print_topic(topicid)

>>> print lda.print_topics()
None
>>> for i in range(0, lda.num_topics-1):
>>>  print lda.print_topic(i)
0.083*response + 0.083*interface + 0.083*time + 0.083*human + 0.083*user + 0.083*survey + 0.083*computer + 0.083*eps + 0.083*trees + 0.083*system
...
于 2013-02-22T03:00:39.590 回答
11

我认为 show_topics 的语法随着时间的推移发生了变化:

show_topics(num_topics=10, num_words=10, log=False, formatted=True)

对于 num_topics 个主题,返回 num_words 个最重要的词(每个主题 10 个词,默认情况下)。

主题以列表形式返回——如果格式化为 True,则返回字符串列表,如果为 False,则返回(概率,单词)2 元组列表。

如果 log 为 True,也将此结果输出到 log。

与 LSA 不同,LDA 中的主题之间没有自然顺序。因此,返回的所有主题的 num_topics <= self.num_topics 子集是任意的,并且可能在两次 LDA 训练运行之间发生变化。

于 2015-04-29T09:04:56.953 回答
7

我认为将主题视为单词列表总是更有帮助。以下代码片段有助于实现该目标。我假设您已经有一个名为lda_model.

for index, topic in lda_model.show_topics(formatted=False, num_words= 30):
    print('Topic: {} \nWords: {}'.format(idx, [w[0] for w in topic]))

在上面的代码中,我决定显示属于每个主题的前 30 个单词。为简单起见,我展示了我得到的第一个主题。

Topic: 0 
Words: ['associate', 'incident', 'time', 'task', 'pain', 'amcare', 'work', 'ppe', 'train', 'proper', 'report', 'standard', 'pmv', 'level', 'perform', 'wear', 'date', 'factor', 'overtime', 'location', 'area', 'yes', 'new', 'treatment', 'start', 'stretch', 'assign', 'condition', 'participate', 'environmental']
Topic: 1 
Words: ['work', 'associate', 'cage', 'aid', 'shift', 'leave', 'area', 'eye', 'incident', 'aider', 'hit', 'pit', 'manager', 'return', 'start', 'continue', 'pick', 'call', 'come', 'right', 'take', 'report', 'lead', 'break', 'paramedic', 'receive', 'get', 'inform', 'room', 'head']

我不太喜欢上述主题的外观,因此我通常将代码修改为如下所示:

for idx, topic in lda_model.show_topics(formatted=False, num_words= 30):
    print('Topic: {} \nWords: {}'.format(idx, '|'.join([w[0] for w in topic])))

...并且输出(显示的前 2 个主题)将如下所示。

Topic: 0 
Words: associate|incident|time|task|pain|amcare|work|ppe|train|proper|report|standard|pmv|level|perform|wear|date|factor|overtime|location|area|yes|new|treatment|start|stretch|assign|condition|participate|environmental
Topic: 1 
Words: work|associate|cage|aid|shift|leave|area|eye|incident|aider|hit|pit|manager|return|start|continue|pick|call|come|right|take|report|lead|break|paramedic|receive|get|inform|room|head
于 2018-10-22T22:29:43.233 回答
6

您是否使用任何日志记录?print_topics如文档中所述打印到日志文件

正如@mac389 所说,lda.show_topics()这是打印到屏幕的方法。

于 2013-03-04T08:58:12.523 回答
5

使用 Gensim 清理它自己的主题格式。

from gensim.parsing.preprocessing import preprocess_string, strip_punctuation,
strip_numeric

lda_topics = lda.show_topics(num_words=5)

topics = []
filters = [lambda x: x.lower(), strip_punctuation, strip_numeric]

for topic in lda_topics:
    print(topic)
    topics.append(preprocess_string(topic[1], filters))

print(topics)

输出 :

(0, '0.020*"business" + 0.018*"data" + 0.012*"experience" + 0.010*"learning" + 0.008*"analytics"')
(1, '0.027*"data" + 0.020*"experience" + 0.013*"business" + 0.010*"role" + 0.009*"science"')
(2, '0.026*"data" + 0.016*"experience" + 0.012*"learning" + 0.011*"machine" + 0.009*"business"')
(3, '0.028*"data" + 0.015*"analytics" + 0.015*"experience" + 0.008*"business" + 0.008*"skills"')
(4, '0.014*"data" + 0.009*"learning" + 0.009*"machine" + 0.009*"business" + 0.008*"experience"')


[
  ['business', 'data', 'experience', 'learning', 'analytics'], 
  ['data', 'experience', 'business', 'role', 'science'], 
  ['data', 'experience', 'learning', 'machine', 'business'], 
  ['data', 'analytics', 'experience', 'business', 'skills'], 
  ['data', 'learning', 'machine', 'business', 'experience']
]
于 2019-08-28T04:07:15.987 回答
3

这是打印主题的示例代码:

def ExtractTopics(filename, numTopics=5):
    # filename is a pickle file where I have lists of lists containing bag of words
    texts = pickle.load(open(filename, "rb"))

    # generate dictionary
    dict = corpora.Dictionary(texts)

    # remove words with low freq.  3 is an arbitrary number I have picked here
    low_occerance_ids = [tokenid for tokenid, docfreq in dict.dfs.iteritems() if docfreq == 3]
    dict.filter_tokens(low_occerance_ids)
    dict.compactify()
    corpus = [dict.doc2bow(t) for t in texts]
    # Generate LDA Model
    lda = models.ldamodel.LdaModel(corpus, num_topics=numTopics)
    i = 0
    # We print the topics
    for topic in lda.show_topics(num_topics=numTopics, formatted=False, topn=20):
        i = i + 1
        print "Topic #" + str(i) + ":",
        for p, id in topic:
            print dict[int(id)],

        print ""
于 2014-05-07T21:45:23.030 回答
3

您可以使用:

for i in  lda_model.show_topics():
    print i[0], i[1]
于 2016-08-01T09:42:23.977 回答
1

最近,在使用 Python 3 和 Gensim 2.3.0 时遇到了类似的问题。print_topics()show_topics()没有给出任何错误,但也没有打印任何东西。结果是show_topics()返回一个列表。所以一个人可以简单地做:

topic_list = show_topics()
print(topic_list)
于 2017-10-29T21:33:02.187 回答
1

您还可以将每个主题的热门单词导出到 csv 文件。topn控制每个主题下要导出的单词数。

import pandas as pd

top_words_per_topic = []
for t in range(lda_model.num_topics):
    top_words_per_topic.extend([(t, ) + x for x in lda_model.show_topic(t, topn = 5)])

pd.DataFrame(top_words_per_topic, columns=['Topic', 'Word', 'P']).to_csv("top_words.csv")

CSV 文件具有以下格式

Topic Word  P  
0     w1    0.004437  
0     w2    0.003553  
0     w3    0.002953  
0     w4    0.002866  
0     w5    0.008813  
1     w6    0.003393  
1     w7    0.003289  
1     w8    0.003197 
... 
于 2018-06-14T22:18:53.667 回答
0
****This code works fine but I want to know the topic name instead of Topic: 0 and Topic:1, How do i know which topic this word comes in**?** 



for index, topic in lda_model.show_topics(formatted=False, num_words= 30):
        print('Topic: {} \nWords: {}'.format(idx, [w[0] for w in topic]))

Topic: 0 
Words: ['associate', 'incident', 'time', 'task', 'pain', 'amcare', 'work', 'ppe', 'train', 'proper', 'report', 'standard', 'pmv', 'level', 'perform', 'wear', 'date', 'factor', 'overtime', 'location', 'area', 'yes', 'new', 'treatment', 'start', 'stretch', 'assign', 'condition', 'participate', 'environmental']
Topic: 1 
Words: ['work', 'associate', 'cage', 'aid', 'shift', 'leave', 'area', 'eye', 'incident', 'aider', 'hit', 'pit', 'manager', 'return', 'start', 'continue', 'pick', 'call', 'come', 'right', 'take', 'report', 'lead', 'break', 'paramedic', 'receive', 'get', 'inform', 'room', 'head']
于 2019-02-14T06:18:27.383 回答