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我正在尝试根据数组中的项目数量从 plist 创建一个循环这是我的 plist 代码

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<array>
<dict>
    <key>question</key>
    <string>2 + 2 = ?</string>
    <key>A</key>
    <string>2</string>
    <key>B</key>
    <string>4</string>
    <key>C</key>
    <string>3</string>
    <key>Ans</key>
    <string>B</string>
</dict>
<dict>
    <key>question</key>
    <string>2 + 4 = ?</string>
    <key>A</key>
    <string>3</string>
    <key>B</key>
    <string>6</string>
    <key>C</key>
    <string>9</string>
    <key>Ans</key>
    <string>B</string>
</dict>
</array>
</plist>

所以我的数组中有两个项目。我希望屏幕加载第一个项目并显示它，然后使用界面中的按钮再次显示屏幕和第二个项目列表

- (void)viewDidLoad
{
[super viewDidLoad];
rootArray = [NSArray arrayWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"question" ofType:@"plist"]];
currentQuestion = -1;
[self showNextQuestion];
}
-(void) showNextQuestion{
    currentQuestion++;
    int numItems = [rootArray count];
    NSMutableArray *question = [NSMutableArray arrayWithCapacity:numItems];
    NSMutableArray *A = [NSMutableArray arrayWithCapacity:numItems];
    NSMutableArray *B = [NSMutableArray arrayWithCapacity:numItems];
    NSMutableArray *C = [NSMutableArray arrayWithCapacity:numItems];
    NSMutableArray *CorrectAns = [NSMutableArray arrayWithCapacity:numItems];

for (NSDictionary *itemData in rootArray) {
    [question addObject:[itemData objectForKey:@"question"]];
    [A addObject:[itemData objectForKey:@"A"]];
    [B addObject:[itemData objectForKey:@"B"]];
    [C addObject:[itemData objectForKey:@"C"]];
    [CorrectAns addObject:[itemData objectForKey:@"Ans"]];
    self.questionasked.text =question[currentQuestion];
    self.answer1.text = A[currentQuestion];
    self.answer2.text = B[currentQuestion];
    self.answer3.text = C[currentQuestion];

    }
}

我知道我必须创建某种循环并使用一个动作，但我不确定如何

4

1 回答 1

1

您已经在 rootArray 中获得了所有内容，因此您不需要使用 NSMutableArrays 做所有这些事情。只是做类似的事情

NSDictionary *item = rootArray[currentQuestion];
self.questionasked.text = item[@"question"];
self.answer1.text = item[@"A"];

并设置一个调用 [self showNextQuestion] 的 UIButton；当你点击它时。

于 2013-02-21T23:28:31.000 回答