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这是在 Excel 中进行的一个非常简单的计算,但我很难理解如何在 Access 中使用不同记录中的表中的 2 个字段来执行此操作。我有一个应用程序需要找到操作 STOPTime 和下一个 STARTTime 之间的区别。任何帮助将不胜感激。我是 VBA 新手。

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2 回答 2

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Sub samPle()
Dim startTime As Date
Dim endTime As Date

startTime = Time
'''Your Code


endTime = Time

Debug.Print DateDiff("n", startTime, endTime) ' difference in minutes

End Sub
于 2013-02-21T19:03:26.710 回答
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根据您的数据,有多种方法可以解决问题,这使得发布有关 SQL 问题的数据非常重要。例如:

桌子:

ID  EventTime           EventType
1   17/02/2013 08:52:00 start
2   17/02/2013 09:52:00 stop
3   17/02/2013 11:52:00 start
4   17/02/2013 15:52:00 stop

SQL:

SELECT a.id,
       a.eventtime                    AS Start,
       a.eventtype,
       (SELECT TOP 1 eventtime
        FROM   times b
        WHERE  eventtype = "stop"
               AND eventtime > a.eventtime
        ORDER  BY eventtime,
                  id)                 AS Stop,
       Datediff("n", [start], [stop]) AS RunTime
FROM   times AS a
WHERE  (( ( a.eventtype ) = "start" ))
ORDER  BY a.eventtime;

结果:

ID  Start               EventType   Stop                RunTime
1   17/02/2013 08:52:00 start       17/02/2013 09:52:00     60
3   17/02/2013 11:52:00 start       17/02/2013 15:52:00     240

重新评论

SELECT a.id, 
       a.eventtime                         AS Start, 
       a.eventtype, 
       (SELECT TOP 1 eventtime 
        FROM   times b 
        WHERE  eventtype = "stop" 
               AND eventtime > a.eventtime 
        ORDER  BY eventtime, 
                  id)                      AS Stop, 
       Datediff("n", [start], [stop])      AS RunTime, 
       (SELECT TOP 1 eventtime 
        FROM   times b 
        WHERE  eventtype = "start" 
               AND eventtime > a.eventtime 
        ORDER  BY eventtime, 
                  id)                      AS NextStart, 
       Datediff("n", [start], [nextstart]) AS StartDiff, 
       Datediff("n", [stop], [nextstart])  AS DownTime 
FROM   times AS a 
WHERE  (( ( a.eventtype ) = "start" )) 
ORDER  BY a.eventtime; 
于 2013-02-21T21:00:05.073 回答