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我有这个查询。它创建了一个日历，用于比较与 DOS 之间的医疗索赔，以计算不同的天数。

当我运行它时，我似乎删除了一些没有出现在我的结果中的行。

谁能明白为什么这些行不会在此查询中计算在内？

ICN 从服务日期到服务日期 详细信息状态代码
12345 20121102 12:00:00 20121103 12:00:00
12345 20121102 12:00:00 20121103 12:00:00
12345 20121102 12:00:00 20121103 12:00:00
12345 20121102 12:00:00 20121103 12:00:00
12345 20121102 12:00:00 20121103 12:00:00
12345 20121102 12:00:00 20121103 12:00:00
12345 20121102 12:00:00 20121103 12:00:00
12345 20121102 12:00:00 20121103 12:00:00
CREATE TABLE #Calendar1(Dt DATETIME NOT NULL PRIMARY KEY);
;WITH cte AS
(
    SELECT CAST('20120101' AS DATETIME) AS c 
    UNION ALL
    SELECT DATEADD(dd,1,c) FROM cte 
    WHERE c < '20131231'
)
INSERT INTO #Calendar1 SELECT c FROM cte OPTION  (MAXRECURSION 1);


SELECT
    ICN,
    COUNT(DISTINCT Dt) AS Days
FROM
    AllOPBYDOS s
    INNER JOIN #Calendar1 c ON
        s.[from Date of service] >= c.Dt AND s.[to Date of service] < c.Dt+1
--Where [Detail Status Code] = 'p'

GROUP BY
    ICN;
4

1 回答 1

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当我在 SQL Server 2008 上运行日历查询时，它只产生一行。我想你想要：

INSERT INTO #Calendar1 SELECT c FROM cte OPTION  (MAXRECURSION 0);

对于删除的行，您确定它们在日历范围内有日期吗？您可能应该进行左外连接并检查极端情况：

SELECT ICN, COUNT(DISTINCT Dt) AS Days,
       sum(case when [from Date of service] not between const.mindt and const.maxdt or
                     [to Date of service] not between const.mindt and const.maxdt
                then 1
                else 0
           end) as OutOfRangeRecords
FROM AllOPBYDOS s left outer JOIN
     #Calendar1 c
     ON s.[from Date of service] >= c.Dt AND s.[to Date of service] < c.Dt+1 cross join
     (select MAX(dt) as maxdt, MIN(dt) as mindt from #Calendar1) const
GROUP BY ICN;
于 2013-02-21T16:14:19.227 回答