1

我已经制作了一个选项面板，但我无法让按钮按预期执行。我试图将 action 设置为连接到面板的 int，但这不起作用。

Object[] choices = null;
    Object[] options = { "Criticals", "Pure Damage", "Heal 300 points", "Flee" };
    JOptionPane.showOptionDialog(null, "What will you do?", "action",
            JOptionPane.DEFAULT_OPTION, JOptionPane.QUESTION_MESSAGE,
            null, options, options[0]);

    switch (action)
    {
    case 0: 
        int Criticals = (int) (Math.random()*500);
        Criticals++;
        caitlyn.enemyhealth = (caitlyn.enemyhealth-Criticals);
        JOptionPane.showMessageDialog(null, "Caitlyn now has" +" " + caitlyn.enemyhealth + "HP left");
        break;
    case 1:
        int PureDamage = (int) (Math.random()*300);
        PureDamage++;
        caitlyn.enemyhealth = (caitlyn.enemyhealth-PureDamage);
        JOptionPane.showMessageDialog(null, "Caitlyn now has" + " " + caitlyn.enemyhealth + "HP left");
        break;
    case 2:
        int heal = 300;
        heal++;
        newchamp.health = (newchamp.health+heal);
        JOptionPane.showMessageDialog(null,  "You now have"+ " " + newchamp.health + "HP points!");
        break;

另外，我不知道我将如何做到这一点，以便已经完成的伤害或治疗被保存并在下一次攻击时保持在该水平，而不是返回默认值。

4

1 回答 1

3

我认为你需要：

    int action = JOptionPane.showOptionDialog(null, "What will you do?", "action",
        JOptionPane.DEFAULT_OPTION, JOptionPane.QUESTION_MESSAGE,
        null, options, options[0]);

您忽略了该方法的返回值，该值告诉您按下了哪个按钮。

于 2013-02-21T13:17:25.533 回答