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我试图让用户能够在搜索表单的一个字段中选择多个记录。

像这样的东西：

<%= f.input_field :neighborhood_id, collection: Neighborhood.order(:name), :url => autocomplete_neighborhood_name_searches_path, :as => :autocomplete, 'data-delimiter' => ',', :multiple => true, :class => "span8" %>

它像这样将它发送到我的search模型：@search = Search.create!(params[:search])

这就是Search.rb模型对它的作用：

key = "%#{keywords}%"
listings = Listing.order(:headline)
listings = listings.includes(:neighborhood).where("listings.headline like ? or neighborhoods.name like ?", key, key) if keywords.present?
listings = listings.where(neighborhood_id: neighborhood_id) if neighborhood_id.present?
listings

问题是这只是接受 1 neighborhood_id，所以当我选择多个对象时出现此错误：

undefined method `to_i' for ["Alley Park, Madison"]:Array

WhereAlley Park和Madison是 2 个社区的名称，而不是 ID。

那么我如何让这个工作呢？

谢谢。

编辑 1

问题似乎不在于params[:search]本身的查找，而在于将表单输入转换为条目数组。我尝试将搜索方法更改为：

listings = listings.includes(:neighborhood).where("neighborhoods.name like ?", neighborhood_id) if neighborhood_id.present?

不要挂断我正在抬头neighborhood.name和经过的事实neighborhood_id。我这样做是因为我知道该字段的参数neighborhood_id实际上是neighborhood. 如果这行得通，我会重构一些东西，但它没有。所以不要挂断电话。

但这仍然返回错误undefined method 'to_i'....

此外，即使我只传入 1 个选项，我仍然会收到该错误。

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2 回答 2

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listings = listings.where("neighborhood_id in (?) ", neighborhood_id)
于 2013-02-21T11:49:24.540 回答
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You can get the id instead of neighborhood names from the input field like this:

<%= f.input_field :neighborhood_id, collection: Neighborhood.order(:name), :url => autocomplete_neighborhood_name_searches_path, :as => :autocomplete, 'data-delimiter' => ',', :multiple => true, :class => "span8", :input_html => { :id => "neighborhood_id" } %>
于 2013-02-21T12:19:24.000 回答