首先, foo 是一个 Func<T1,T2,TResult> 对象。有可能做类似的事情
Func<T2,T1,TResult> bar = ConvertFunction(foo);
因此将 Func<T1,T2,TResult> 转换为 Func<T2,T1,TResult>。
是的,这是可能的:
Func<T2, T1, TResult> bar = (t2, t1) => foo(t1, t2);
这基本上创建了另一个具有切换参数的委托,该委托在内部简单地调用原始委托。如果您只有 a而不是 a ,
这是执行这种“转换”的唯一方法。Func<T1, T2, TResult>
Expression<Func<T1, T2, TResult>>
这是功能:
class MyFuncConverter<T1, T2, TResult>
{
static Func<T1, T2, TResult> _foo;
public static Func<T2, T1, TResult> ConvertFunction(Func<T1, T2, TResult> foo)
{
_foo = foo;
return new Func<T2, T1, TResult>(MyFunc);
}
private static TResult MyFunc(T2 arg2, T1 arg1)
{
return _foo(arg1, arg2);
}
}
示例用法:
static void Main(string[] args)
{
var arg1 = 10;
var arg2 = "abc";
// create a Func with parameters in reversed order
Func<string, int, string> testStringInt =
MyFuncConverter<int, string, string>.ConvertFunction(TestIntString);
var result1 = TestIntString(arg1, arg2);
var result2 = testStringInt(arg2, arg1);
// testing results
Console.WriteLine(result1 == result2);
}
/// <summary>
/// Sample method
/// </summary>
private static string TestIntString(int arg1, string arg2)
{
byte[] toEncodeAsBytes = System.Text.ASCIIEncoding.ASCII
.GetBytes(arg2.ToString() + arg1);
string returnValue = System.Convert.ToBase64String(toEncodeAsBytes);
return returnValue;
}