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我在解析 Facebook 的 FQL 多查询时遇到了一些麻烦。我不知道我需要如何处理结果中具有相同名称的 JSONArray -> fql_result_set。这是我得到的 FQL JSON。

{
"data": [
{
  "name": "query1", 
  "fql_result_set": [
    {
      "uid": uid1, 
      "eid": eid1, 
      "rsvp_status": "attending"
    }, 
    {
      "uid": uid2, 
      "eid": eid2, 
      "rsvp_status": "attending"
    }, 
    {
      "uid": uid3, 
      "eid": eid3, 
      "rsvp_status": "attending"
    }
  ]
}, 
{
  "name": "query2", 
  "fql_result_set": [
    {
      "uid": uid1, 
      "name": "name1", 
      "pic_square": "pic1"
    }, 
    {
      "uid": uid2, 
      "name": "name2", 
      "pic_square": "pic2"
    }, 
    {
      "uid": uid3, 
      "name": "name3", 
      "pic_square": "pic3"
    }
  ]
}
]
}

这是我目前在我的 Java 代码中得到的，但我没有得到任何回报。我得到的数据最终会进入一个 ArrayList。

try {
            GraphObject go = response.getGraphObject();
            JSONObject jso = go.getInnerJSONObject();
            JSONArray data = jso.getJSONArray("data");
            for(int i = 0; i < data.length(); i++){
                JSONObject o1 = data.getJSONObject(i);
                JSONArray rs1 = o1.getJSONArray("fql_result_set");
                for(int j = 0; j < rs1.length(); j++){
                    JSONObject rso1 = rs1.getJSONObject(j);
                    String uid = rso1.getString("uid");
                    String eid = rso1.getString("eid");
                    String rsvp = rso1.getString("rsvp_status");
                }
                JSONObject o2 = data.getJSONObject(i);
                JSONArray rs2 = o2.getJSONArray("fql_result_set");
                for(int k = 0; k < rs2.length(); k++){
                    JSONObject rso2 = rs2.getJSONObject(k);
                    String name = rso2.getString("name");
                    String pic = rso2.getString("pic_square");
                }

            }
} catch (JSONException e) {
            e.printStackTrace();
        }

有谁知道我需要如何解析这个 JSON 结果？提前致谢！

解决方案

try {
            people = new ArrayList<Person>();
            GraphObject go = response.getGraphObject();
            JSONObject jso = go.getInnerJSONObject();
            JSONArray data = jso.getJSONArray("data").getJSONObject(0)
                    .getJSONArray("fql_result_set");
            JSONArray data2 = jso.getJSONArray("data").getJSONObject(1)
                    .getJSONArray("fql_result_set");


            for (int i = 0; i < data.length(); i++) {
                Person p = new Person();
                JSONObject o1 = data.getJSONObject(i);
                uid = o1.getString("uid");
                p.setUserId(uid);
                p.setRsvp_status(o1.getString("rsvp_status"));


                for (int j = 0; j < data2.length(); j++) {
                    JSONObject o2 = data2.getJSONObject(j);
                    if (p.getUserId().equals(o2
                            .getString("uid"))) {
                        p.setName(o2.getString("name"));
                        p.setPic(o2.getString("pic_square"));
                    }
                }
                people.add(p);
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
4

2 回答 2

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// assign the whole result to a JSON Object
JSONObject result = whatever-variable-name

// get 'data' JSONArray
JSONArray array = result.getJSONArray('data')

// loop
for(i = 0; i < array.length(); i++) {
 JSONObject obj = array.getJSONObject(i);
 **
 name = obj.getString('name');
}

** 此时 obj 是"name": "query1", "fql_result_set": [ { "uid": uid1, "eid": eid1, "rsvp_status": "attending" }, { "uid": uid2, "eid": eid2, "rsvp_status": "attending" }, { "uid": uid3, "eid": eid3, "rsvp_status": "attending" } ]

并name具有值query1或query2取决于循环计数。您能否使用迄今为止访问fql_result_set": [ { "uid": uid1, "eid": eid1, "rsvp_status": "attending" }, { "uid": uid2, "eid": eid2, "rsvp_status": "attending" }, { "uid": uid3, "eid": eid3, "rsvp_status": "attending" } ]GLHF 的方法！

于 2013-02-21T07:46:15.037 回答
0

尝试这个：

 String strEvents = new JSONArray(apiResponse).getJSONObject(0).toString();
 String strVenues= new JSONArray(apiResponse).getJSONObject(1).toString();
 jsonArray  = new JSONObject(strEvents).getJSONArray("fql_result_set");
 jsonVenues = new JSONObject(strVenues).getJSONArray("fql_result_set");
于 2013-06-14T01:28:10.330 回答