sql - 如何防止对空值进行算术运算？

Question

使用 Oracle11g：

如果该列为空，我想排除该列上的算术。

在这种情况下，我怎样才能让seqno=1的lag_diff为null？

   with detail_records as (
    select 1 seqno, 10 set_a  from dual union all
    select 2 seqno, 10 set_a  from dual union all
    select 3 seqno, 20 set_a  from dual union all
    select 4 seqno, 30 set_a  from dual )
  select  seqno,
          set_a,
          lag_val,
    case (lag_val - set_a)
    when 0 then 'AAA'
    else  'BBB'
    end  as lag_diff
 from ( select seqno, 
        set_a, 
        lag(set_a,1) over (order by seqno) as lag_val       
  from detail_records)
order by seqno

期望的结果

  SEQNO  SET_A LAG_VAL LAG_DIFF
  ----------------------------
  1       10  <NULL>   <null>
  2       10   10       AAA
  3       20   10       BBB
  4       30   20       BBB

Answer 1

将您的情况更改为以下内容：

 with detail_records as (
    select 1 seqno, 10 set_a  from dual union all
    select 2 seqno, 10 set_a  from dual union all
    select 3 seqno, 20 set_a  from dual union all
    select 4 seqno, 30 set_a  from dual )
  select  seqno,
          set_a,
          lag_val,
    case 
    when (lag_val - set_a) is null then null
    when (lag_val - set_a) = 0 then 'AAA'
    else  'BBB'
    end  as lag_diff
 from ( select seqno, 
        set_a, 
        lag(set_a,1) over (order by seqno) as lag_val       
  from detail_records)
order by seqno