0

我有多个关联数组，类似于以下内容：

$arr1 = array(0 => 12, 5 => 10, 19 => 48);
$arr2 = array(0 => 14, 7 => 9, 12 => 11, 19 => 30);

我想合并这些数组，以便我有一组键（0、5、7、12、19），每个键都指向一个包含原始数组值的数组，null如果该值不存在于原始数组：

$merge = array(
    0 => array(12, 14),
    5 => array(10, null),
    7 => array(null, 9),
    12 => array(null, 11),
    19 => array(48, 30)
);

我需要能够为任意数量的数组执行此操作。我不知道从哪里开始。

我想，我可以遍历每个数组，将它的值附加到结果中 - 但在将当前值附加到该索引之前，我必须检查每个结果数组中是否有必要数量的元素 - 这是效率不是很高。

想法或指针？

4

4 回答 4

1

编辑

<?php
$arr1 = array(0 => 12, 5 => 10, 19 => 48);
$arr2 = array(0 => 14, 7 => 9, 12 => 11, 19 => 30);

foreach($arr1 as $k => $v){
 if(array_key_exists($k, $arr2)){
   $newarr[$k][] = $v;
   $newarr[$k][] = $arr2[$k];
 }else{
   $newarr[$k][] = $v;
   $newarr[$k][] = 'NULL';
 }
}

foreach($arr2 as $k => $v){
 if(!array_key_exists($k, $arr1)){
   $newarr[$k][] = 'NULL';
   $newarr[$k][] = $v;
 }
}

ksort($newarr);

echo '<pre>';
print_r($newarr);
?>

输出：

   Array
(
    [0] => Array
        (
            [0] => 12
            [1] => 14
        )

    [5] => Array
        (
            [0] => 10
            [1] => NULL
        )

    [7] => Array
        (
            [0] => NULL
            [1] => 9
        )

    [12] => Array
        (
            [0] => NULL
            [1] => 11
        )

    [19] => Array
        (
            [0] => 48
            [1] => 30
        )

)
于 2013-02-20T18:36:11.467 回答
1

我想这就是你要找的。

/*Merge function*/
function merge($a1, $a2)
{
    foreach($a1 as $key => $val)
        $a1[$key] = Array($a1[$key], null);
    foreach($a2 as $key => $val)
        $a1[$key] = Array((isset($a1[$key]))? $a1[$key][0]: null, $val);
    return ksort($a1);
}

/*Test*/
$arr1 = array(0 => 12, 5 => 10, 19 => 48);
$arr2 = array(0 => 14, 7 => 9, 12 => 11, 19 => 30);

foreach(merge($arr1, $arr2) as $key => $val){
    echo "<br />$key --";
    print_r($val);
}
/*output*/
0 --Array ( [0] => 12 [1] => 14 )
5 --Array ( [0] => 10 [1] => )
7 --Array ( [0] => [1] => 9 )
12 --Array ( [0] => [1] => 11 ) 
19 --Array ( [0] => 48 [1] => 30 )
于 2013-02-20T18:59:15.113 回答
1 
    $arr1 = array(0 => 12, 5 => 10, 19 => 48);
    $arr2 = array(0 => 14, 7 => 9, 12 => 11, 19 => 30);

    $keys = array_merge(array_keys($arr1), array_keys($arr2));
    $merged = array();
    foreach ($keys as $key) {
        $merged[$key] = array(); 
        $merged[$key][] = isset($arr1[$key]) ? $arr1[$key] : null;
        $merged[$key][] = isset($arr2[$key]) ? $arr2[$key] : null;            
    }
    ksort($merged);
    echo '<pre>', var_dump($merged), '</pre>';

针对任意数量的数组进行了修改

    $arrays = array(
        array(0 => 12, 5 => 10, 19 => 48),
        array(0 => 14, 7 => 9, 12 => 11, 19 => 30),
        // ... more arrays
    );

    $keys = array();
    foreach ($arrays as $arr) {
        $keys = array_merge($keys, array_keys($arr));
    }

    $merged = array();
    foreach ($keys as $key) {
        $merged[$key] = array();
        foreach ($arrays as $arr) {
            $merged[$key][] = isset($arr[$key]) ? $arr[$key] : null;
        }         
    }
    ksort($merged);
    echo '<pre>', var_dump($merged), '</pre>';
于 2013-02-20T19:05:15.800 回答
0

试试这个功能：

   function multimerge ($array1, $array2) {
      if (is_array($array2) && count($array2)) {
         foreach ($array2 as $k => $v) {
            if (is_array($v) && count($v)) {
                $array1[$k] = multimerge($array1[$k], $v);
            } else {
                $array1[$k] = $v;
            }
         }
       } else {
          $array1 = $array2;
       }

       return $array1;
   }

http://php.net/manual/en/function.array-merge.php

于 2013-02-20T18:41:23.947 回答