0

我需要根据多列中的信息检查重复记录。如果我只使用一列来检查，我可以让它工作，但我需要它来检查三列，如果所有三列都匹配，则显示敬酒。下面的代码运行，但没有写入数据库。如果我从 if 语句中删除两个字符串，它可以正常工作并写入数据库。我曾尝试使用多个游标，但在尝试检查多个列是否有重复项时，我得到了相同的结果。

private void saveState() {

    Calendar calendar = Calendar.getInstance();
    SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
    eventDate = sdf.format(calendar.getTime());

    String date = eventDate;
    String event = eventTitle.getText().toString();
    String empID = result;

    Cursor cursor = mDbHelper.fetchAllEntries();

    while (cursor.moveToNext()) {

    String enteredDate = cursor.getString(cursor.getColumnIndex("date"));
    String enteredEvent = cursor.getString(cursor.getColumnIndex("event"));
    String enteredEmpId = cursor.getString(cursor.getColumnIndex("empID"));

        if ( (enteredEmpId.equals(empID)) && (enteredDate.equals("date") && (enteredEvent.equals(event)))) {
            Toast.makeText(this, "Employee has already been scanned for this event.", Toast.LENGTH_LONG).show();  
        } else {
            mDbHelper.createEntry(date, event, empID);
        }
    }
}

如果需要，这也是我的 Helper 类中的 fetchAllEntries() ：

public Cursor fetchAllEntries() {

    return mDb.query(DATABASE_TABLE, new String[] {KEY_ROWID, KEY_DATE,
            KEY_EVENT, KEY_EMPID}, null, null, null, null, null);
}

编辑：我让它显示吐司，但由于某种原因它仍在写入数据库。我还注意到吐司在屏幕上停留了很长时间。我认为这是因为它在 while 循环中并且在完成之前不会关闭。我之前忘了提到，这个应用程序正在扫描条码，所以它需要能够识别它们是否已经被扫描，以了解扫描发生的日期和事件。这是更新的代码

private void saveState() {

    Calendar calendar = Calendar.getInstance();
    SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
    eventDate = sdf.format(calendar.getTime());

    String date = eventDate;
    String event = eventTitle.getText().toString();
    String empID = result;

    Cursor cursor = mDbHelper.fetchAllEntries();

    if (cursor.getCount() == 0) {

        mDbHelper.createEntry(date, event, empID);

    } else if (cursor.getCount() > 0 ) {

    while (cursor.moveToNext()) {

    String enteredDate = cursor.getString(cursor.getColumnIndex("date"));
    String enteredEvent = cursor.getString(cursor.getColumnIndex("event"));
    String enteredEmpId = cursor.getString(cursor.getColumnIndex("empID"));

         if ((enteredDate.equals(date)) && (enteredEvent.equals(event)) && (enteredEmpId.equals(empID))) {

            Toast.makeText(this, "Employee has already been scanned for this event.", Toast.LENGTH_SHORT).show();  

        } else {

            mDbHelper.createEntry(date, event, empID);

        }
    }
}

}

4

1 回答 1

0

检查是否有超过 1 行具有相同的值：

SELECT COUNT(*) FROM myTable WHERE column1 = 'x' AND column2 = 'y' AND column3 = 'z'

如果 count 超过 1，则有重复，获取第一个这样的行的 id：

SELECT id FROM myTable WHERE column1 = 'x' AND column2 = 'y' AND column3 = 'z' LIMIT 1

现在删除其余的行：

DELETE * FROM myTable WHERE column1 = 'x' AND column2 = 'y' AND column3 = 'z' AND id != myId
于 2013-02-20T17:39:52.147 回答