0

该方法接受任何名称并测试字符是元音还是辅音。如果是元音，则将字符变为大写，如果是辅音，则将字符变为小写。有什么想法吗？我不知道如何在 if else 语句中添加.toUpperCase和。.toLowerCase

public static void parsing(String name[])
{
    String temp = name[0];

    int i = 0;
    for(i = 0; i < temp.length(); i++)
    {
        if(temp.charAt(i) == 'a' || temp.charAt(i) == 'A' ||
           temp.charAt(i) == 'e' || temp.charAt(i) == 'E' ||
           temp.charAt(i) == 'i' || temp.charAt(i) == 'I' ||
           temp.charAt(i) == 'o' || temp.charAt(i) == 'O' ||
           temp.charAt(i) == 'u' || temp.charAt(i) == 'U')
        {
         System.out.print(temp.charAt(i).toUpperCase);
        }//Obviously wrong but I don't know what to do.
            else
            {
            System.out.print(temp.charAt(i).toLowerCase);
            }//Obviously wrong but I don't know what to do.     
    }
4

5 回答 5

2

要转换单个字符，请使用Character类中的方法：

System.out.print(Character.toUpperCase(temp.charAt(i)));
System.out.print(Character.toLowerCase(temp.charAt(i)));
于 2013-02-20T17:29:30.487 回答
1

创建两个最终数组 - 一个带有元音，第二个带有辅音。然后检查循环中的当前字符是元音还是辅音，并进行适当的更改。

于 2013-02-20T17:29:19.827 回答
0

由于 String 是不可变的，因此您正在打头。重建生成的字符串。一个（位次优的）解决方案是：

public static void parsing(String[] names)
{
    for (int i = 0; i < names.length; ++i) {
        names[i] = chAngEd(names[i]);
    }
}

private static String chAngEd(String s) {
    String result = "";
    for (int i = 0; i < s.length(); ++i) {
        char ch = s.charAt(i);
        if (ch == 'a' || ...) {
            ch = Character.toUpperCase(ch);
        } else {
            ch = ...
        }
        result += ch;
    }
    return result;
}
于 2013-02-20T17:34:40.927 回答
0 
public static void parsing(String names[]){
   for (int i=0; i<names.length; ++i){
       names[i] = capitaliseConsts(names[i]);
   }
}


private static String capitaliseConsts(String name){
    StringBuilder sb = new StringBuilder();
    Character c;

    for (int i=0; i<name.length(); ++i){
        c = name.charAt(i);
        if (c.equalsIgnoreCase('a') || 
            c.equalsIgnoreCase('e') ||
            c.equalsIgnoreCase('i') ||
            c.equalsIgnoreCase('o') ||
            c.equalsIgnoreCase('u')){

          sb.append(Character.toUpperCase(c));
       }
       else{
             sb.append(Character.toLowerCase(c));
       }
    }
    return sb.toString();
}
于 2013-02-20T17:41:17.043 回答
0 
String vowelsArray = "aeiuo";
String constantsArray = "uppercase constants";
int stringLength = name.length();
String givenNameCopy = name.ToString();
for(int i = 0; i < stringLength; i++){
if(vowelsArray.contains(givenNameCopy[i]))
   then uppercase
else if(constantsArray.contains(givenNameCopy[i]))
   then lowercase
else
    continue;

希望这可以帮助。

于 2013-02-20T17:41:55.740 回答