三张桌子
状态 : ID,member_1,member_2 -->
(eg. 12, member_Joseph, member_John ;
22, member_Jacob, member_Jarrod ;
31, member_Jarrod, member_John
11, member_John, member_Jacob)
提交:ID,学生 -->
(eg. 12, Amy ;
22, Brian;
31 Susan ;
11 Kyle)
info : member_name, 联系方式 -->
(eg. member_Joseph, joseph@name.name;
member_Jacob, jacob@name.name ;
member_Jarrod, jarrod@name.name ;
member_John, john@name.name )
从查询构建的新表:
member_Joseph, joseph@name.name, Amy;
member_Jacob, jacob@name.name, Kyle ;
member_Jarrod, jarrod@name.name, Brian, Susan ;
member_John, john@name.name, Amy, Susan, Kyle )
我想制作分配给状态表中每个成员的所有学生的数组,
例如。
array1 --> member_Joseph:学生 1、学生 2、学生 3
array2 --> member_John:学生 2、学生 4、学生 5
array3 -->member_Jacob:学生 3、学生 5、学生 1
那会是:
$query = db_query("
SELECT info.member_name, submit.student
FROM {info}
INNER JOIN {status}
ON info.member_name = status.member_1
INNER JOIN {status}
ON info.member_name = status.member_2
INNER JOIN {submit}
ON submit.id = status.id
");
while($result = db_fetch_array($query)){
echo $result['student']; //iterate through members and print students for each
}
错误是:“不是唯一的表/别名”
(仅供参考:我正在使用 Drupal 6 语法)