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我遇到了几行 jQuery 共存的问题。我相信它们的格式不正确,因为 Blogger 不会让我保存我的代码。目前我有:

<script src='https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js' type='text/javascript'/>
<script type='text/javascript'>

<script src='https://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js' type='text/javascript'/>
<script>
var $jq = jQuery.noConflict();
</script>

<script src='http://blogger-related-posts.googlecode.com/files/jquery.related-posts-widget-2.0.min.js' type='text/javascript'/>

我正在尝试添加脚本,但无法保存我的模板。是我的网站。提前致谢!

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1 回答 1

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关闭脚本标签

 <script src='https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js' type='text/javascript'/></script>


<script src='https://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js' type='text/javascript'/></script>
<script>
var $jq = jQuery.noConflict();
</script>

<script src='http://blogger-related-posts.googlecode.com/files/jquery.related-posts-widget-2.0.min.js' type='text/javascript'/></script>
于 2013-02-20T04:30:41.677 回答