0

我的代码如下：

   #include<stdio.h>
   #include <string.h>
   #include <math.h>
   #include <stdlib.h>
   int string_length(char*);
   void reverse(char*);
   int main(void)
   {
      char num[256];
      printf("%c[%d;%d;%dmPlease enter a number of rows: ", 0x1B, 5, 32, 40);
      gets(num);
      //gets number

printf("%c[%dm\n", 0x1B, 0);
//Resets color

//Variables
char revnum[50], q[50] = "\0", r[50] = "\v";
int i, x, j, z, w;

//Reverses inputted character string
reverse(num);

//Takes reversed inputted character string and out puts it as an integer
for(i = 0; num[i] != '\0'; ++i) {
    j = -(48-num[i]);
    double y = i;
    x = j*pow(10, y) + x;
}

//Takes integer version of inputted character string and assigns a counter's value (counting up to our integer version) to a character string
for (z = 0; z <= x; z++) {
    sprintf(revnum, "%d", z);

    //Takes the new character string for each number up to the inputted value and prints it vertically, but no differentiating between numbers and printing them horizontally to each other
    for (w = 0; revnum[w] != '\0'; ++w) {
        strcat(q, r);
        printf("%s", q);
        strcat(q, revnum[w]);
      }
   }

  }

  //Function which reverses a character string
   void reverse(char *num)
{
int length, c;
char *begin, *end, temp;

length = string_length(num);

begin = num;
end = num;

for ( c = 0 ; c < ( length - 1 ) ; c++ )
    end++;

for ( c = 0 ; c < length/2 ; c++ )
{
    temp = *end;
    *end = *begin;
    *begin = temp;

    begin++;
    end--;
}
}

 int string_length(char *pointer)
 {
int c = 0;

while( *(pointer+c) != '\0' )
    c++;

return c;
}

该程序的重​​点是输出输入数字之前的所有数字，每个数字的数字垂直，然后数字本身水平列出。

请帮忙！！！

4

1 回答 1

0

你犯了几个错误。此代码有效：

#include<stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int string_length(char*);
void reverse(char*);
int main(void)
{
  char num[256];
  printf("Please enter a number of rows: ", 0x1B, 5, 32, 40);
  gets(num);
  //gets number

//Variables
char revnum[50], q[50] = "\0";
int i, x, j, z, w;

//Reverses inputted character string
reverse(num);

//Takes reversed inputted character string and out puts it as an integer
x = atoi(num);

//Takes integer version of inputted character string and assigns a counter's value (counting up to our integer version) to a character string
for (z = 0; z <= x; z++) {
sprintf(revnum, "%d", z);

//Takes the new character string for each number up to the inputted value and prints it vertically, but no differentiating between numbers and printing them horizontally to each other
for (w = 0; revnum[w] != '\0'; ++w) {
    printf("%s\v", q);
char a[2];
sprintf(a,"%c",revnum[w]);
strcat(q,a);
  }
}

}

//Function which reverses a character string
void reverse(char *num)
{
int length, c;
char *begin, *end, temp;

length = string_length(num);

begin = num;
end = num;

for ( c = 0 ; c < ( length - 1 ) ; c++ )
end++;

for ( c = 0 ; c < length/2 ; c++ )
{
temp = *end;
*end = *begin;
*begin = temp;

 begin++;
 end--;
}
}

int string_length(char *pointer)
{
int c = 0;

while( *(pointer+c) != '\0' )
c++;

return c;
}

并使用选项-fno-stack-protector进行编译以防止堆栈碰撞检测。

于 2013-02-20T09:43:52.460 回答