php - 在没有定义排序规则的情况下订购 MySQL 字符串结果？

Question

假设我有以下结果：

Mackay
Mackay Airport
Melbourne
Melbourne Airport
Sydney
Sydney Ac
Sydney Airport

我怎样才能做到让他们总是在他们的顶部订购机场？按字母顺序，例如：

Mackay Airport
Mackay
Melbourne Airport
Melbourne
Sydney Airport
Sydney
Sydney Ac

对如何使机场更加突出有点困惑。

Answer 1

不确定以下查询是否涵盖所有情况，但它似乎适用于您的示例数据：

select name,
SUBSTRING_INDEX(name,'Airport',1)
as l,
LOCATE('Airport',name) as r from 
(
select 'Sydney Airport' as name
union all
select 'Sydney'
union all
select 'Sydney Ac'
union all
select '
Mackay Airport'
union all
select 'Mackay'
union all
select 'Melbourne'
union all
select 'Melbourne Airport'
)a
order by l asc, r desc

用桌子看起来像

select name
from table1 
ORDER BY SUBSTRING_INDEX(name,'Airport',1) ASC,
LOCATE('Airport',name) DESC

Answer 2

似乎您不能同时按整数和字符串排序，但您可以根据“机场”是否存在来派生要排序的字符串。这很愚蠢，但它有效：

ORDER BY IF(name NOT LIKE '% Airport', CONCAT(name, ' Birport'), name)

Answer 3

以下查询将为您提供预期的输出（即使查询很复杂）。

SELECT t.name
FROM (
SELECT @num := IF(@num IS NULL, 1, @num+1) AS number, name
FROM places
ORDER BY IF ((name LIKE '% Airport'), SUBSTRING(name, 1, LOCATE(' Airport', name) - 1), name)     DESC) t
ORDER BY t.number DESC;

这是示例。

http://www.sqlfiddle.com/#!2/117b7/80