php - 如何从查询中排除不需要的记录

Question

我有一个 MySQL 语句，我需要一些帮助。我正在正确提取数据，但我只需要一些帮助，排除不需要的记录。如果候选人剩余尝试次数等于 0，我不想提取该记录，但如您所见，我正在使用子查询来生成候选人可能进行的重新挖掘尝试次数。

有没有办法使用 WHERE 语句中的剩余尝试字段来排除不需要的记录？

    SELECT (
                SELECT  count(*) AS Number_Attempts_Used
                FROM    candidate_exam_record
                WHERE   candidate_exam_record.idcandidate_eligibilty = candidate_eligibilty.idcandidate_eligibilty
            ) AS remaining_attempts
            , (
                SELECT CASE WHEN count(*) > '0' THEN candidate_exam_record.idcandidate_eligibilty END
                FROM candidate_exam_record
                WHERE candidate_exam_record.idcandidate_eligibilty = candidate_eligibilty.idcandidate_eligibilty) AS EL_ID
    FROM    candidate_eligibilty
            INNER JOIN candidate ON candidate_eligibilty.idcandidate = candidate.idcandidate
            INNER JOIN exam ON candidate_eligibilty.exam_id = exam.exam_id
            INNER JOIN jurisdiction ON exam.jurisdiction_id = jurisdiction.jurisdiction_id
    WHERE   jurisdiction.jurisdiction_id = 'xxxx' 
            AND candidate_eligibilty.eligibility_end_date >= '2013-02-19'
            AND remaining_attempts > '0'

Answer 1

它很乱，但对我来说看起来还可以。尝试更改'0'为只是简单的 old 0。我假设您将其存储为 INT ，对吗？