我的查询有问题，但我不知道是什么原因造成的，所以我需要你的帮助 =)
我得到以下异常：
PreparedStatementCallback; 错误的 SQL 语法 [选择 USERNAME 作为用户名，密码作为密码，来自 ams.user where USERNAME=?]; 嵌套异常是 com.mysql.jdbc.exceptions.MySQLSyntaxErrorException: You have an error in your SQL syntax; 检查与您的 MySQL 服务器版本相对应的手册，以在第 1 行的“from ams.user where USERNAME='admin'”附近使用正确的语法
这是我的 login.jsp：
<div class="box">
<h1><spring:message code="login.description" /></h1>
<br/>
<form name='f' action="<c:url value='j_spring_security_check' />" method='POST'>
<ol>
<li>
<label><spring:message code="user.user" />:</label>
<em><img src="images/star_red.png" alt="required"></img></em>
<input type='text' name='j_username'>
</li>
<li>
<label><spring:message code="user.password" />:</label>
<em><img src="images/star_red.png" alt="required"></img></em>
<input type='password' name='j_password' />
</li>
<li>
<label> </label>
<input type='hidden' name='remember_me' id="remember_hidden" value="false"/>
<input type='checkbox' id='remember_checkbox' onchange="toggleRememberMe()" class="checkbox"/>
<spring:message code="login.remember" />
</li>
<li>
<label> </label>
<input type="submit" value="<spring:message code="login"/>"/>
</li>
</ol>
<br />
<br />
</form>
<c:if test="${not empty param.login_error}">
<div class="error">
<br />
<spring:message code="login.error" />
<br />
<spring:message code="login.errorReason" />:
<c:out value="${SPRING_SECURITY_LAST_EXCEPTION.message}" />
</div>
</c:if>
</div>
这是我的安全上下文代码：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:security="http://www.springframework.org/schema/security"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<!-- <security:http auto-config="true" access-decision-manager-ref="accessDecisionManager"> -->
<security:http auto-config="true">
<security:intercept-url pattern="/login/login.do" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/login/doLogin.do" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/lib/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/css/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/images/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/resources/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/**" access="IS_AUTHENTICATED_REMEMBERED" />
<security:form-login login-page="/login/login.do" authentication-failure-url="/login/login.do?login_error=true" default-target-url="/test/showTest.do"/>
<security:logout logout-success-url="/login/login.do" invalidate-session="true" />
<security:remember-me key="rememberMe"/>
</security:http>
<security:authentication-manager>
<security:authentication-provider>
<security:jdbc-user-service data-source-ref="dataSource"
users-by-username-query="select USERNAME as username, PASSWORD as password, from ams.user where USERNAME=?"
authorities-by-username-query="
select distinct user.USERNAME as username, permission.NAME as authority
from ams.user, ams.user_role, ams.role, ams.role_permission, ams.permission
where user.ID=user_role.USER_ID AND user_role.ROLE_ID=role_permission.ROLE_ID AND role_permission.PERMISSION_ID=permission.ID AND user.EMAIL=?"/>
<security:password-encoder ref="passwordEncoder" />
</security:authentication-provider>
</security:authentication-manager>
<bean id="passwordEncoder"
class="org.springframework.security.authentication.encoding.ShaPasswordEncoder">
<constructor-arg value="256" />
</bean>
</beans>
有谁知道可能导致此错误的原因？非常感谢您对此的帮助=）