0

我正在用python编写一个程序，允许用户输入班级学生人数，然后为每个学生输入3个测试成绩。它还需要显示学生的考试平均成绩、班级平均成绩以及班级中的最高和最低平均成绩。现在，在打印每个学生的成绩和平均水平后，我无法让它不打印班级平均水平。我也真的无法使最大值和最小值起作用，因为它随着每个学生的变化而变化为该学生的平均值。 

students=int(input('Please enter the number of students in the class: '))

for number in range(students):

    class_average == 0 

    first_grade=int(input("Enter student's first grade: "))
    second_grade=int(input("Enter student's second grade: "))
    third_grade=int(input("Enter student's third grade: "))


    StudentAverage=(first_grade + second_grade + third_grade)/3
    print("The student's average is", round(StudentAverage,2))



    class_average= class_average + StudentAverage
    print("The class average is", round(class_average/students,2))



maximum_num = 0

if StudentAverage > maximum_num:
    maximum= StudentAverage
    print("The maxiumum average is", round(maximum,2))


minimum_num = 100

if StudentAverage < minimum_num:
    minimum= StudentAverage
    print("The minimum average is", round(minimum,2))
4

1 回答 1

2

我将您的初始化程序移到了循环之外，因此在每次迭代期间该值不会重置。我将最大和最小比较移到循环中，并替换了最大和最小变量。每个新值分别小于和大于这些值，因此需要使用 maximum_num 和 minimum_num 来代替。运行班级平均值太低，因为它使用学生总数而不是当前计算的人数。我用数字+1代替了学生的使用。我认为这是您想要的代码。

students=int(input('Please enter the number of students in the class: '))
class_average = 0 
maximum_num = 0
minimum_num = 100
for number in range(students):

  first_grade=int(input("Enter student's first grade: "))
  second_grade=int(input("Enter student's second grade: "))
  third_grade=int(input("Enter student's third grade: "))

  StudentAverage=(first_grade + second_grade + third_grade)/3
  print("The student's average is", round(StudentAverage,2))

  class_average= class_average + StudentAverage
  print("The class average is", round(class_average/(number+1),2))

  if StudentAverage > maximum_num:
    maximum_num = StudentAverage

  if StudentAverage < minimum_num:
    minimum_num = StudentAverage
print("The minimum average is", round(minimum_num,2))
print("The maxiumum average is", round(maximum_num,2))
于 2013-02-19T21:20:32.093 回答