python - 尝试在python中读取文件

Question

请任何人都可以帮我阅读python中的.txt文件

这是我的代码

flink open(2of12inf.txt, "rU")   

但我收到一个错误

Answer 1

您忘记了=赋值语句和引号：

flink = open('2of12inf.txt', "rU")   

最好将文件作为上下文管理器（with语句）打开，以便它自动关闭：

with open('2of12inf.txt', "rU") as flink:
    # do something with the open file object

# flink will be closed automatically.

flink是一个文件对象，所以你可以使用 , 等方法.read()来.readline()读取它。或者您可以遍历对象（迭代）以每次获取单行：

with open('2of12inf.txt', "rU") as flink:
    for line in flink:
        # do something with each line.

我会使用文件的绝对路径而不是相对路径以避免意外：

with open('/path/to/directory/with/2of12inf.txt', "rU") as flink:

或者您可以使用该os.path库来构造绝对路径：

import os.path

filename = os.path.expanduser('~/2of12inf.txt')

with open(filename, "rU") as flink:

例如，打开一个2of12inf.text在当前用户主目录中命名的文件。

Answer 2

您可能应该将文件名括在引号中（并在 flink 和 open 之间添加一个赋值运算符）：

flink = open("2of12inf.txt", "rU")

正如 IT Ninja 所说，我也强烈建议使用 with 构造打开文件：

with open("2of12inf.txt", "rU") as flink:
    # do stuff...

这将像使用 try-finally 块一样关闭文件。

Answer 3

使用以下示例：

#!/usr/bin/python
# open file
f = open ("/etc/passwd","r")

#Read whole file into data
data = f.read()

# Print it
print data

# Close the file
f.close()