12

我会用 FOSUserBundle 为 Symfony2 编写一个测试。

目前我尝试了一些方法，但没有人工作。

我需要一个像“createAuthClient”这样的函数。

这是我的基础课。我发布它是因为您可以更好地理解我的问题。

<?php
use Symfony\Bundle\FrameworkBundle\Test\WebTestCase;
use Symfony\Component\Security\Core\Authentication\Token\UsernamePasswordToken;
use Symfony\Component\BrowserKit\Cookie;

class WebTestMain extends WebTestCase
{
    protected static $container;

    static protected function createClient(array $options = array(), array $server = array())
    {
        $client = parent::createClient($options, $server);

        self::$container = self::$kernel->getContainer();

        return $client;
    }

    static function createAuthClient(array $options = array(), array $server = array())
    {
        // see lines below with my tries
    }
}

第一次尝试：

if(static::$kernel === null)
{
    static::$kernel = static::createKernel($options);
    static::$kernel->boot();
}
if(static::$container === null)
{
    self::$container = self::$kernel->getContainer();
}

$parameters = self::$container->getParameter('test');
$server = array_merge(array('HTTP_HOST' => $parameters['host'], 'HTTP_USER_AGENT' => $parameters['useragent']), $server);

$client = self::createClient($options, $server);

$userProvider = self::$container->get('fos_user.user_manager');
$user = $userProvider->findUserBy(array('id' => 1));
$client->getCookieJar()->set(new Cookie('MOCKSESSID', true));
$session = self::$kernel->getContainer()->get('session');
$token = new UsernamePasswordToken($user, null, 'main', $user->getRoles());
$client->getContainer()->get('security.context')->setToken($token);
$session->set('_security_main', serialize($token));

return $client;

然后我搜索和搜索......我的第二次尝试。

if(static::$kernel === null)
{
    static::$kernel = static::createKernel($options);
    static::$kernel->boot();
}
if(static::$container === null)
{
    self::$container = self::$kernel->getContainer();
}

$parameters = self::$container->getParameter('test');
$server = array_merge(
    array(
        'HTTP_HOST' => $parameters['host'],
        'HTTP_USER_AGENT' => $parameters['useragent'],
        'PHP_AUTH_USER' => 'admin',
        'PHP_AUTH_PW'   => 'admin'
    ),
    $server
);
$client = static::createClient(array(), array());
$client->followRedirects();
return $client;

这是我发布这个问题之前的最后一次尝试......

$client = self::createClient($options, $server);

$parameters = self::$container->getParameter('test');
$server = array_merge(
    array(
        'HTTP_HOST' => $parameters['host'],
        'HTTP_USER_AGENT' => $parameters['useragent']
    ),
    $server
);

$client->setServerParameters($server);

$usermanager = self::$container->get('fos_user.user_manager');
$testuser = $usermanager->createUser();
$testuser->setUsername('test');
$testuser->setEmail('test@mail.org');
$testuser->setPlainPassword('test');
$usermanager->updateUser($testuser);

return $client;

先感谢您。

4

2 回答 2

17

我发现使用经过身份验证的用户进行测试的最佳方法是访问您的登录页面并使用您从夹具加载的用户名和密码提交表单。这可能看起来很慢而且很麻烦，但会测试用户实际会做什么。您甚至可以创建自己的方法来快速轻松地使用它。

public function doLogin($username, $password) {
   $crawler = $this->client->request('GET', '/login');
   $form = $crawler->selectButton('_submit')->form(array(
       '_username'  => $username,
       '_password'  => $password,
       ));     
   $this->client->submit($form);

   $this->assertTrue($this->client->getResponse()->isRedirect());

   $crawler = $this->client->followRedirect();
}
于 2013-02-19T16:03:37.557 回答
15

创建一个AbstractControllerTest并创建一个授权客户端，setUp()如下所示：

<?php
// ...
use Symfony\Component\BrowserKit\Cookie;

abstract class AbstractControllerTest extends WebTestCase
{
    /**
     * @var Client
     */
    protected $client = null;


    public function setUp()
    {
        $this->client = $this->createAuthorizedClient();
    }

    /**
     * @return Client
     */
    protected function createAuthorizedClient()
    {
        $client = static::createClient();
        $container = $client->getContainer();

        $session = $container->get('session');
        /** @var $userManager \FOS\UserBundle\Doctrine\UserManager */
        $userManager = $container->get('fos_user.user_manager');
        /** @var $loginManager \FOS\UserBundle\Security\LoginManager */
        $loginManager = $container->get('fos_user.security.login_manager');
        $firewallName = $container->getParameter('fos_user.firewall_name');

        $user = $userManager->findUserBy(array('username' => 'REPLACE_WITH_YOUR_TEST_USERNAME'));
        $loginManager->loginUser($firewallName, $user);

        // save the login token into the session and put it in a cookie
        $container->get('session')->set('_security_' . $firewallName,
            serialize($container->get('security.context')->getToken()));
        $container->get('session')->save();
        $client->getCookieJar()->set(new Cookie($session->getName(), $session->getId()));

        return $client;
    }
}

注意：请用您的测试用户名替换用户名。

然后，扩展AbstractControllerTest并使用全局$client发出请求，如下所示：

class ControllerTest extends AbstractControllerTest
{
    public function testIndexAction()
    {
        $crawler = $this->client->request('GET', '/admin/');

        $this->assertEquals(
            Response::HTTP_OK,
            $this->client->getResponse()->getStatusCode()
        );
    }
}

该方法经过测试并且工作正常

于 2014-12-01T07:06:21.450 回答