在这里,我有两个应该相互同步的运行方法。
轮询类:
*/
public void run() {
int seqId = 0;
while(true) {
List<KpiMessage> list = null;
try{
if(!accumulator.isUsed){
try {
list = fullPoll(seqId);
if (!list.isEmpty()) {
seqId = list.get(0).getSequence();
accumulator.manageIngoing(list);
}
System.out.println("Updated");
wait();
} catch (Exception e1) {
e1.printStackTrace();
}
}
} catch (Exception e){
// TODO:
System.err.println(e.getMessage());
e.printStackTrace();
}
}
}
/**
* Method which defines polling of the database and also count the number of Queries
* @param lastSeq
* @return pojo col
* @throws Exception
*/
public List<KpiMessage> fullPoll(int lastSeq) throws Exception {
Statement st = dbConnection.createStatement();
System.out.println("Polling");
ResultSet rs = st.executeQuery("Select * from msg_new_to_bde where ACTION = 814 and
STATUS = 200 order by SEQ DESC");
List<KpiMessage> pojoCol = new ArrayList<KpiMessage>();
try {
while (rs.next()) {
KpiMessage filedClass = convertRecordsetToPojo(rs);
pojoCol.add(filedClass);
}
for (KpiMessage pojoClass : pojoCol) {
System.out.print(" " + pojoClass.getSequence());
System.out.print(" " + pojoClass.getTableName());
System.out.print(" " + pojoClass.getAction());
System.out.print(" " + pojoClass.getKeyInfo1());
System.out.print(" " + pojoClass.getKeyInfo2());
System.out.print(" "+ pojoClass.getStatus());
System.out.println(" " + pojoClass.getEntryTime());
}
} finally {
try {
st.close();
rs.close();
} catch (Exception e) {
System.err.println(e.getMessage());
e.printStackTrace();
}
}
处理和更新类:
public void run() {
while(true){
try {
while(!accumulator.isUsed)
{
try {
System.out.println("Waiting for new outgoingmessages");
this.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
Collection<KpiMessage> outgoingQueue = generate(accumulator.outgoingQueue);
accumulator.manageOutgoing(outgoingQueue, dbConnection);
} catch (Exception e) {
System.err.println(e.getMessage());
e.printStackTrace();
}
}
}
}
我有一个逻辑错误:
轮询器不仅轮询新消息,而且从第一个开始一次又一次地读取数据库。
也是一次又一次的更新。
如何解决这个同步问题。