如何在mysql中拆分名称字符串？
例如：
name
-----
Sachin ramesh tendulkar
Rahul dravid
拆分名称，如firstname,middlename,lastname：
firstname middlename lastname
--------- ------------ ------------
sachin ramesh tendulkar
rahul dravid
问问题
358272 次
17 回答
220
我已将此答案分为两（2）种方法。第一种方法会将您的全名字段分为名字、中间名和姓氏。如果没有中间名，中间名将显示为 NULL。
SELECT
SUBSTRING_INDEX(SUBSTRING_INDEX(fullname, ' ', 1), ' ', -1) AS first_name,
If( length(fullname) - length(replace(fullname, ' ', ''))>1,
SUBSTRING_INDEX(SUBSTRING_INDEX(fullname, ' ', 2), ' ', -1) ,NULL)
as middle_name,
SUBSTRING_INDEX(SUBSTRING_INDEX(fullname, ' ', 3), ' ', -1) AS last_name
FROM registeredusers
第二种方法将中间名视为姓氏的一部分。我们只会从您的全名字段中选择名字和姓氏列。
SELECT
SUBSTRING_INDEX(SUBSTRING_INDEX(fullname, ' ', 1), ' ', -1) AS first_name,
TRIM( SUBSTR(fullname, LOCATE(' ', fullname)) ) AS last_name
FROM registeredusers
您可以使用 substr、locate、substring_index 等做很多很酷的事情。查看手册是否有一些真正的困惑。http://dev.mysql.com/doc/refman/5.0/en/string-functions.html
于 2013-02-19T06:26:14.327 回答
44
MySQL 中没有字符串拆分功能。所以你必须创建自己的功能。这将对您有所帮助。更多细节在这个链接。
功能：
CREATE FUNCTION SPLIT_STR(
x VARCHAR(255),
delim VARCHAR(12),
pos INT
)
RETURNS VARCHAR(255)
RETURN REPLACE(SUBSTRING(SUBSTRING_INDEX(x, delim, pos),
LENGTH(SUBSTRING_INDEX(x, delim, pos -1)) + 1),
delim, '');
用法：
SELECT SPLIT_STR(string, delimiter, position)
例子：
SELECT SPLIT_STR('a|bb|ccc|dd', '|', 3) as third;
+-------+
| third |
+-------+
| ccc |
+-------+
于 2013-02-19T05:35:29.433 回答
22
好吧，我没有使用任何东西，所以我决定创建一个真正简单的拆分函数，希望它有所帮助：
DECLARE inipos INTEGER;
DECLARE endpos INTEGER;
DECLARE maxlen INTEGER;
DECLARE item VARCHAR(100);
DECLARE delim VARCHAR(1);
SET delim = '|';
SET inipos = 1;
SET fullstr = CONCAT(fullstr, delim);
SET maxlen = LENGTH(fullstr);
REPEAT
SET endpos = LOCATE(delim, fullstr, inipos);
SET item = SUBSTR(fullstr, inipos, endpos - inipos);
IF item <> '' AND item IS NOT NULL THEN
USE_THE_ITEM_STRING;
END IF;
SET inipos = endpos + 1;
UNTIL inipos >= maxlen END REPEAT;
于 2013-08-13T20:01:44.587 回答
19
这是我使用的拆分功能：
--
-- split function
-- s : string to split
-- del : delimiter
-- i : index requested
--
DROP FUNCTION IF EXISTS SPLIT_STRING;
DELIMITER $
CREATE FUNCTION
SPLIT_STRING ( s VARCHAR(1024) , del CHAR(1) , i INT)
RETURNS VARCHAR(1024)
DETERMINISTIC -- always returns same results for same input parameters
BEGIN
DECLARE n INT ;
-- get max number of items
SET n = LENGTH(s) - LENGTH(REPLACE(s, del, '')) + 1;
IF i > n THEN
RETURN NULL ;
ELSE
RETURN SUBSTRING_INDEX(SUBSTRING_INDEX(s, del, i) , del , -1 ) ;
END IF;
END
$
DELIMITER ;
SET @agg = "G1;G2;G3;G4;" ;
SELECT SPLIT_STRING(@agg,';',1) ;
SELECT SPLIT_STRING(@agg,';',2) ;
SELECT SPLIT_STRING(@agg,';',3) ;
SELECT SPLIT_STRING(@agg,';',4) ;
SELECT SPLIT_STRING(@agg,';',5) ;
SELECT SPLIT_STRING(@agg,';',6) ;
于 2014-10-21T16:15:07.397 回答
15
您也可以使用 bewlo one：
SELECT SUBSTRING_INDEX(Name, ' ', 1) AS fname,
SUBSTRING_INDEX(SUBSTRING_INDEX(Name,' ', 2), ' ',-1) AS mname,
SUBSTRING_INDEX(Name, ' ', -1) as lname FROM mytable;
于 2013-02-19T07:30:17.247 回答
3
select (case when locate('(', LocationName) = 0
then
horse_name
else
left(LocationName, locate('(', LocationName) - 1)
end) as Country
from tblcountry;
于 2018-09-20T06:24:11.013 回答
2
concat(upper(substring(substring_index(NAME, ' ', 1) FROM 1 FOR 1)), lower(substring(substring_index(NAME, ' ', 1) FROM 2 FOR length(substring_index(NAME, ' ', 1))))) AS fname,
CASE
WHEN length(substring_index(substring_index(NAME, ' ', 2), ' ', -1)) > 2 THEN
concat(upper(substring(substring_index(substring_index(NAME, ' ', 2), ' ', -1) FROM 1 FOR 1)), lower(substring(substring_index(substring_index(f.nome, ' ', 2), ' ', -1) FROM 2 FOR length(substring_index(substring_index(f.nome, ' ', 2), ' ', -1)))))
ELSE
CASE
WHEN length(substring_index(substring_index(f.nome, ' ', 3), ' ', -1)) > 2 THEN
concat(upper(substring(substring_index(substring_index(f.nome, ' ', 3), ' ', -1) FROM 1 FOR 1)), lower(substring(substring_index(substring_index(f.nome, ' ', 3), ' ', -1) FROM 2 FOR length(substring_index(substring_index(f.nome, ' ', 3), ' ', -1)))))
END
END
AS mname
于 2019-10-31T14:18:31.493 回答
2
SELECT
p.fullname AS 'Fullname',
SUBSTRING_INDEX(p.fullname, ' ', 1) AS 'Firstname',
SUBSTRING(p.fullname, LOCATE(' ',p.fullname),
(LENGTH(p.fullname) - (LENGTH(SUBSTRING_INDEX(p.fullname, ' ', 1)) + LENGTH(SUBSTRING_INDEX(p.fullname, ' ', -1))))
) AS 'Middlename',
SUBSTRING_INDEX(p.fullname, ' ', -1) AS 'Lastname',
(LENGTH(p.fullname) - LENGTH(REPLACE(p.fullname, ' ', '')) + 1) AS 'Name Qt'
FROM people AS p
LIMIT 100;
解释：
查找名字和姓氏很容易，您只需使用 SUBSTR_INDEX 函数 Magic发生在中间名中，其中使用 SUBSTR 和 Locate 查找全名的第一个空格位置和 LENGTH - (LENGTH firstname + LENGTH lastname) 以获取所有中间名。
请注意，名字和姓氏的长度是使用 SUBSTR_INDEX 计算的
于 2017-06-28T12:20:39.550 回答
2
在空格分隔符的第二个实例之后获取字符串的其余部分
SELECT
SUBSTRING_INDEX(SUBSTRING_INDEX('Sachin ramesh tendulkar', ' ', 1), ' ', -1) AS first_name,
SUBSTRING_INDEX(SUBSTRING_INDEX('Sachin ramesh tendulkar', ' ', 2), ' ', -1)
AS middle_name,
SUBSTRING('Sachin ramesh tendulkar',LENGTH(SUBSTRING_INDEX('Sachin ramesh tendulkar', ' ', 2))+1) AS last_name
于 2015-12-09T13:19:54.217 回答
1
CREATE DEFINER=`root`@`localhost` FUNCTION `getNameInitials`(`fullname` VARCHAR(500), `separator` VARCHAR(1)) RETURNS varchar(70) CHARSET latin1
DETERMINISTIC
BEGIN
DECLARE `result` VARCHAR(500) DEFAULT '';
DECLARE `position` TINYINT;
SET `fullname` = TRIM(`fullname`);
SET `position` = LOCATE(`separator`, `fullname`);
IF NOT `position`
THEN RETURN LEFT(`fullname`,1);
END IF;
SET `fullname` = CONCAT(`fullname`,`separator`);
SET `result` = LEFT(`fullname`, 1);
cycle: LOOP
SET `fullname` = SUBSTR(`fullname`, `position` + 1);
SET `position` = LOCATE(`separator`, `fullname`);
IF NOT `position` OR NOT LENGTH(`fullname`)
THEN LEAVE cycle;
END IF;
SET `result` = CONCAT(`result`,LEFT(`fullname`, 1));
-- SET `result` = CONCAT_WS(`separator`, `result`, `buffer`);
END LOOP cycle;
RETURN upper(`result`);
END
1.在mysql中执行这个函数。2.这将创建一个函数。现在你可以在任何你想要的地方使用这个功能。
SELECT `getNameInitials`('Kaleem Ul Hassan', ' ') AS `NameInitials`;
3. 上面的getNameInitials第一个参数是要过滤的字符串，第二个参数是要分隔字符串的旁观者角色。4. 在上面的例子中，'Kaleem Ul Hassan' 是名字，我想得到首字母，我的分隔符是空格''。
于 2016-10-09T04:41:24.160 回答
1
您可以使用common_schema并使用该tokenize功能。有关这方面的更多信息，请点击链接。你的代码最终会像：
call tokenize(name, ' ');
但是，请注意空格不是名字和姓氏的可靠分隔符。例如，在西班牙，有两个姓氏是很常见的。
于 2016-04-27T07:26:18.320 回答
1
我们将课程名称和章节名称的值存储在单列章节名称中。
像这样存储的值：“JAVA：多态”
您需要检索 CourseName : JAVA 和 ChapterName : Polymorphism
下面是要检索的 SQL 选择查询。
SELECT
SUBSTRING_INDEX(SUBSTRING_INDEX(ChapterName, ' ', 1), ' ', -1) AS
CourseName,
REPLACE(TRIM(SUBSTR(ChapterName, LOCATE(':', ChapterName)) ),':','') AS
ChapterName
FROM Courses where `id`=1;
如果对此有任何疑问，请告诉我。
于 2018-07-10T07:37:48.437 回答
0
要在空格分隔符的第二个实例之后获取字符串的其余部分：
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(MsgRest, ' ', 1), ' ', -1) AS EMailID
, SUBSTRING_INDEX(SUBSTRING_INDEX(MsgRest, ' ', 2), ' ', -1) AS DOB
, IF(
LOCATE(' ', `MsgRest`) > 0,
TRIM(SUBSTRING(SUBSTRING(`MsgRest`, LOCATE(' ', `MsgRest`) +1),
LOCATE(' ', SUBSTRING(`MsgRest`, LOCATE(' ', `MsgRest`) +1)) +1)),
NULL
) AS Person
FROM inbox
于 2014-06-22T14:58:19.563 回答
0
在这里结合一些答案来创建一个返回字符串部分的 SP。
drop procedure if exists SplitStr;
DELIMITER ;;
CREATE PROCEDURE `SplitStr`(IN Str VARCHAR(2000), IN Delim VARCHAR(1))
BEGIN
DECLARE inipos INT;
DECLARE endpos INT;
DECLARE maxlen INT;
DECLARE fullstr VARCHAR(2000);
DECLARE item VARCHAR(2000);
create temporary table if not exists tb_split
(
item varchar(2000)
);
SET inipos = 1;
SET fullstr = CONCAT(Str, delim);
SET maxlen = LENGTH(fullstr);
REPEAT
SET endpos = LOCATE(delim, fullstr, inipos);
SET item = SUBSTR(fullstr, inipos, endpos - inipos);
IF item <> '' AND item IS NOT NULL THEN
insert into tb_split values(item);
END IF;
SET inipos = endpos + 1;
UNTIL inipos >= maxlen END REPEAT;
SELECT * from tb_split;
drop table tb_split;
END;;
DELIMITER ;
于 2019-09-16T15:38:18.070 回答
0
首先创建程序如下：
CREATE DEFINER=`root`@`%` PROCEDURE `sp_split`(str nvarchar(6500), dilimiter varchar(15), tmp_name varchar(50))
BEGIN
declare end_index int;
declare part nvarchar(6500);
declare remain_len int;
set end_index = INSTR(str, dilimiter);
while(end_index != 0) do
/* Split a part */
set part = SUBSTRING(str, 1, end_index - 1);
/* insert record to temp table */
call `sp_split_insert`(tmp_name, part);
set remain_len = length(str) - end_index;
set str = substring(str, end_index + 1, remain_len);
set end_index = INSTR(str, dilimiter);
end while;
if(length(str) > 0) then
/* insert record to temp table */
call `sp_split_insert`(tmp_name, str);
end if;
END
之后创建过程如下：
CREATE DEFINER=`root`@`%` PROCEDURE `sp_split_insert`(tb_name varchar(255), tb_value nvarchar(6500))
BEGIN
SET @sql = CONCAT('Insert Into ', tb_name,'(item) Values(?)');
PREPARE s1 from @sql;
SET @paramA = tb_value;
EXECUTE s1 USING @paramA;
END
如何调用测试
CREATE DEFINER=`root`@`%` PROCEDURE `test_split`(test_text nvarchar(255))
BEGIN
create temporary table if not exists tb_search
(
item nvarchar(6500)
);
call sp_split(test_split, ',', 'tb_search');
select * from tb_search where length(trim(item)) > 0;
drop table tb_search;
END
call `test_split`('Apple,Banana,Mengo');
于 2015-11-23T10:37:35.007 回答
0
根据以前的答案并做一些修改......
笔记：
p_delimiter必须是VARCHAR(1)couse CHAR(1)if is ' '(space) give ''(删除空格并返回空字符串)
而不是使用LENGTHI prefer CHAR_LENGTHwhich is safe for multibyte characters likeUTF
DROP FUNCTION IF EXISTS FN_SPLIT_STR;
DELIMITER ;;
CREATE FUNCTION FN_SPLIT_STR(
p_input VARCHAR(2000), p_delimiter VARCHAR(1), p_position INT
)
RETURNS VARCHAR(2000)
DETERMINISTIC
BEGIN
DECLARE chunks INT;
SET chunks := CHAR_LENGTH(p_input) - CHAR_LENGTH(REPLACE(p_input, p_delimiter, '')) + 1;
IF p_position > chunks THEN
RETURN NULL;
END IF;
RETURN SUBSTRING_INDEX(SUBSTRING_INDEX(p_input, p_delimiter, p_position), p_delimiter, -1);
END;;
DELIMITER ;
于 2022-01-27T15:50:34.200 回答
0
DELIMITER $$
DROP FUNCTION IF EXISTS `split_name`$$
CREATE FUNCTION split_name (p_fullname TEXT, p_part INTEGER)
RETURNS TEXT
READS SQL DATA
BEGIN
DECLARE v_words INT UNSIGNED;
DECLARE v_name TEXT;
SET p_fullname=RTRIM(LTRIM(p_fullname));
SET v_words=(SELECT SUM(LENGTH(p_fullname) - LENGTH(REPLACE(p_fullname, ' ', ''))+1));
IF v_words=1 THEN
IF p_part=1 THEN
SET v_name=p_fullname;
ELSEIF p_part=2 THEN
SET v_name=NULL;
ELSEIF p_part=3 THEN
SET v_name=NULL;
ELSE
SET v_name=NULL;
END IF;
ELSEIF v_words=2 THEN
IF p_part=1 THEN
SET v_name=SUBSTRING(p_fullname, 1, LOCATE(' ', p_fullname) - 1);
ELSEIF p_part=2 THEN
SET v_name=SUBSTRING(p_fullname, LOCATE(' ', p_fullname) + 1);
ELSEIF p_part=3 THEN
SET v_name=NULL;
ELSE
SET v_name=NULL;
END IF;
ELSEIF v_words=3 THEN
IF p_part=1 THEN
SET v_name=SUBSTRING(p_fullname, 1, LOCATE(' ', p_fullname) - 1);
ELSEIF p_part=2 THEN
SET p_fullname=SUBSTRING(p_fullname, LOCATE(' ', p_fullname) + 1);
SET v_name=SUBSTRING(p_fullname, 1, LOCATE(' ', p_fullname) - 1);
ELSEIF p_part=3 THEN
SET p_fullname=REVERSE (SUBSTRING(p_fullname, LOCATE(' ', p_fullname) + 1));
SET p_fullname=SUBSTRING(p_fullname, 1, LOCATE(' ', p_fullname) - 1);
SET v_name=REVERSE(p_fullname);
ELSE
SET v_name=NULL;
END IF;
ELSEIF v_words>3 THEN
IF p_part=1 THEN
SET v_name=SUBSTRING(p_fullname, 1, LOCATE(' ', p_fullname) - 1);
ELSEIF p_part=2 THEN
SET p_fullname=REVERSE(SUBSTRING(p_fullname, LOCATE(' ', p_fullname) + 1));
SET p_fullname=SUBSTRING(p_fullname, LOCATE(' ', p_fullname,SUBSTRING_INDEX(p_fullname,' ',1)+1) + 1);
SET v_name=REVERSE(p_fullname);
ELSEIF p_part=3 THEN
SET p_fullname=REVERSE (SUBSTRING(p_fullname, LOCATE(' ', p_fullname) + 1));
SET p_fullname=SUBSTRING(p_fullname, 1, LOCATE(' ', p_fullname) - 1);
SET v_name=REVERSE(p_fullname);
ELSE
SET v_name=NULL;
END IF;
ELSE
SET v_name=NULL;
END IF;
RETURN v_name;
END;
SELECT split_name('Md. Obaidul Haque Sarker',1) AS first_name,
split_name('Md. Obaidul Haque Sarker',2) AS middle_name,
split_name('Md. Obaidul Haque Sarker',3) AS last_name
于 2016-05-24T06:09:42.687 回答