1

我创建了 2 个 UIButton（不同的标签）并连接到 1 个动作，但是当同时按下时，它会以很小的延迟触发 2 个动作。

- (IBAction)keysPress:(UIButton *)sender {
    UIButton *butOne = (UIButton *)[sender viewWithTag:0];
    UIButton *butTwo = (UIButton *)[sender viewWithTag:1];
    NSLog(@"BUT 1: %@ || BUT 2: %@",butOne, butTwo);
}

始终记录 2 次：

2013-02-19 09:37:40.933 TestActions[1107:c07] BUT 1: <UIButtonLabel: 0xca4d450; frame = (65 67; 9 19); text = 'â'; clipsToBounds = YES; opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0xca4d4c0>> || BUT 2: <UIRoundedRectButton: 0xca4d310; frame = (161 164; 139 153); opaque = NO; autoresize = RM+BM; tag = 1; layer = <CALayer: 0xca4d270>>

2013-02-19 09:37:40.935 TestActions[1107:c07] BUT 1: <UIRoundedRectButton: 0xca4c5c0; frame = (20 164; 135 153); opaque = NO; autoresize = RM+BM; layer = <CALayer: 0xca4c6b0>> || BUT 2: (null)

如何控制这种情况？2 个按钮，1 个动作 - 开火 1 次。

4

2 回答 2

5

你似乎不明白它sender是什么。发送者是触发事件的按钮，您可以根据它的内容进行编程。

您需要保存对按钮的引用，然后在进入函数时将它们与发送者进行比较。

@property (nonatomic, weak) IBOutlet UIButton *butOne;
@property (nonatomic, weak) IBOutlet UIButton *butTwo;

-(IBAction)keysPress:(UIButton *)sender {
   if(sender == [self butOne]) {
       //Do button one actions
   } 

   if(sender == [self butTwo]) {
       //Do button two actions
   }
}

如果您不想保留引用并使用这些viewWithTag东西，我真的不建议这样做，但如果您这样做，您可以：

- (IBAction)keysPress:(UIButton *)sender {
   UIButton *butOne = (UIButton *)[self viewWithTag:1];
   UIButton *butTwo = (UIButton *)[self viewWithTag:2];
   if(sender == butOne) {
       //Do button one actions
   } 

   if(sender == butTwo) {
       //Do button two actions
   }
}
于 2013-02-19T02:48:16.523 回答
2 
- (IBAction)keysPress:(UIButton *)sender {
    if(_canClick)
    {
        _canClick = NO;
        UIButton *butOne = (UIButton *)[sender viewWithTag:0];
        UIButton *butTwo = (UIButton *)[sender viewWithTag:1];
        NSLog(@"BUT 1: %@ || BUT 2: %@",butOne, butTwo);
        [self performSelector:@selector(makeButtonCanClick) withObject:nil afterDelay:YOURTIMEINTERVAL];
    }

}

- (void)makeButtonCanClick
{
    _canClick = YES;
}

_canClick是一个BOOLivar ，默认是YES

于 2013-02-19T02:54:56.570 回答