12

我有这样的方法：

private bool Method_1(Expression<Func<IPerson, bool>> expression)
{
    /* Some code that will call Method_2 */
}

在这种方法中，我想将IPerson类型更改为另一种类型。我想调用另一个看起来像这样的方法：

private bool Method_2(Expression<Func<PersonData, bool>> expression)
{
    /* Some code */
}

所以，在method_1我需要更改IPerson为PersonData. 我怎样才能做到这一点？

编辑：

当我打电话时：Method_1(p => p.Id == 1)我想“保存”条件 ( p.Id == 1) 但我想在另一种类型上执行此条件，即IPerson. 所以，我需要改变表达式或创建一个新的表达式IPerson

4

2 回答 2

22

如果您使用 .net 4 很容易（更新：如评论中所述，ExpressionVisitor是在版本 4 而不是 4.5 中添加的）它需要对旧框架进行一些谷歌搜索：

有一些假设，但我认为它们对您的 DTO 和实体场景有效 - 访问的属性必须匹配。

class PersonData
{
    public bool Prop { get; set; }
}

interface IPerson 
{
    bool Prop { get; set; }
}

在 .net 4 中ExpressionVisitor定义了一个类，如果您使用较旧的类，这会使这变得容易得多，那么您需要编写或找到它的实现：

class Visitor<T> : ExpressionVisitor
{
    ParameterExpression _parameter;

    //there must be only one instance of parameter expression for each parameter 
    //there is one so one passed here
    public Visitor(ParameterExpression parameter)
    {
        _parameter = parameter;
    }

    //this method replaces original parameter with given in constructor
    protected override Expression VisitParameter(ParameterExpression node)
    {
        return _parameter;
    }

    //this one is required because PersonData does not implement IPerson and it finds
    //property in PersonData with the same name as the one referenced in expression 
    //and declared on IPerson
    protected override Expression VisitMember(MemberExpression node)
    {
        //only properties are allowed if you use fields then you need to extend
        // this method to handle them
        if (node.Member.MemberType != System.Reflection.MemberTypes.Property)
            throw new NotImplementedException();

        //name of a member referenced in original expression in your 
        //sample Id in mine Prop
        var memberName = node.Member.Name;
        //find property on type T (=PersonData) by name
        var otherMember = typeof(T).GetProperty(memberName);
        //visit left side of this expression p.Id this would be p
        var inner = Visit(node.Expression);
        return Expression.Property(inner, otherMember);
    }
}

概念证明：

class Program
{
   static void Main()
    {
        //sample expression
        Expression<Func<IPerson, bool>> expression = x => x.Prop;

        //parameter that will be used in generated expression
        var param = Expression.Parameter(typeof(PersonData));
        //visiting body of original expression that gives us body of the new expression
        var body = new Visitor<PersonData>(param).Visit(expression.Body);
        //generating lambda expression form body and parameter 
        //notice that this is what you need to invoke the Method_2
        Expression<Func<PersonData, bool>> lambda = Expression.Lambda<Func<PersonData, bool>>(body, param);
        //compilation and execution of generated method just to prove that it works
        var boolValue = lambda.Compile()(new PersonData());
    }
}

请注意，这适用于简单的表达式。如果你需要处理，x.Prop.Prop1 < 3那么你需要进一步扩展它。

于 2013-02-18T09:32:43.490 回答
0

这是@Rafal 解决方案的改进。它允许对复杂对象的属性调用进行管道化。

//sample expression
Expression<Func<IPerson, bool>> expression = x => x.PropA.PropB.PropC == "ABC";

只需更改otherMember以使用inner.

class Visitor<T> : ExpressionVisitor
{
    ParameterExpression _parameter;

    //there must be only one instance of parameter expression for each parameter 
    //there is one so one passed here
    public Visitor(ParameterExpression parameter)
    {
        _parameter = parameter;
    }

    //this method replaces original parameter with given in constructor
    protected override Expression VisitParameter(ParameterExpression node)
    {
        return _parameter;
    }

    //this one is required because PersonData does not implement IPerson and it finds
    //property in PersonData with the same name as the one referenced in expression 
    //and declared on IPerson
    protected override Expression VisitMember(MemberExpression node)
    {
        //only properties are allowed if you use fields then you need to extend
        // this method to handle them
        if (node.Member.MemberType != System.Reflection.MemberTypes.Property)
            throw new NotImplementedException();

        //name of a member referenced in original expression in your 
        //sample Id in mine Prop
        var memberName = node.Member.Name;
        
        /*Fix*/
        //visit left side of this expression p.Id this would be p
        var inner = Visit(node.Expression);
        //find property on type T (=PersonData) by name
        var otherMember = inner.Type.GetProperty(memberName);

        return Expression.Property(inner, otherMember);
    }
}
于 2022-02-08T12:27:25.610 回答