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I have a controller with a method that looks something like this: 

    public function browsecategory($category_id)
    {               

        //find any subcategories for this category
        $this->load->model('category/category_model');
                    $this->load->model('category/product_category_model');  
        $records['categories'] = $this->category_model->find_all_by('parent_id', $category_id);

                    //add some product data too. 
                    $records['products'] = $this->product_category_model->find_all_by('category_id', $category_id); 
        Template::set('records', $records);
        Template::render();
    }//end browsecategory

All the examples I've seen for the codeigniter pagination "stuff" is using one query. I need to combine two data sets and serve on one view.

Any suggestions?

EDIT 1

I've tried to follow MDeSilva's suggestion below. And although the pagination object is correctly calculating the number of links to create, all items appear on all pages.

Here's the code in the model that gets the data:

public function get_categories_and_products($limit=12, $offset=0, $category_id=null)
{
    print '<BR>the function got the following offeset:'.$offset;
    $query = "(SELECT cat.category_id, cat.title, cat.image_thumb, cat.deleted, cat.display_weight ";
    $query = $query."FROM bf_categories cat ";
    $query = $query."WHERE cat.parent_id=".$category_id;
    $query = $query." AND cat.category_id <>".$category_id;
    $query = $query.") UNION (";
    $query = $query."SELECT p.product_id, p.name, p.image_thumb, p.deleted , p.display_weight";
    $query = $query." FROM bf_product p ";
    $query = $query."Inner join bf_product_category cp ";
    $query = $query."on p.product_id=cp.product_id ";
    $query = $query."Where cp.category_id=".$category_id.")";

    $this->db->limit($limit, $offset);
    $catsandprods= $this->db->query($query);
    return $catsandprods->result() ;
}

And here's the code in the controller: 

public function browsecategory($category_id, $offset=0)
    {
            $this->load->library('pagination');

            $total = $this->product_model->get_cats_prods_count($category_id);

            $config['base_url'] = site_url('/product/browsecategory/'.$category_id);
            $config['uri_segment'] = 4;
            $config['total_rows'] = $total;
            $config['per_page'] = 5;
            $config['num_links'] = 10;

            $this->pagination->initialize($config);
            $offset = ($this->uri->segment($config['uri_segment'])) ? $this->uri->segment($config['uri_segment']) : 0;
                        print $offset;
            //Call the model function here to get the result, 
            $records= $this->product_model->get_categories_and_products(5,$offset,$category_id);
            //add to breadcrumb trail
            $this->build_bread_crumb_trail($category_id);
            $breadcrumbs = $this->breadcrumbs->expand_to_hyperlinks();

            Template::set('currentcategory',$category_id);
            Template::set('breadcrumbs', $breadcrumbs);
            Template::set('records', $records);
            Template::render();     
    }

I've debugged and I can see that the line of code "$this->db->limit($limit, $offset);" in the model is not working. It always returns the full record set... Can you tell me what I'm missing? Thanks.

4

3 回答 3

1

这是在 CI 中生成分页链接的方法，因为您的要求有一个带有连接的查询，

public function index($offset = 0) {
   $language_id = 1;

    $artwork_id = null;

    if ($_SERVER['REQUEST_METHOD'] == 'POST')
    {
        $artwork_id = $this->input->post('serach_artwork_id', TRUE) ? $this->input->post('serach_artwork_id', TRUE) : null;
        $data['artwork_id'] = $artwork_id;

    }

    $this->load->library('pagination');
    $limit = 10;

    $total = $this->Artwork_model->get_artwork_count($language_id, $artwork_id);

    $config['base_url'] = base_url().'artwork/index/';
    $config['total_rows'] = $total;
    $config['per_page'] = $limit;
    $config['uri_segment'] = 3;

    $config['first_link'] = '<< First';
    $config['last_link'] = 'Last >>';
    $config['next_link'] = 'Next ' . '&gt;';
    $config['prev_link'] = '&lt;' . ' Previous';
    $config['num_tag_open'] = '<span class="number">';
    $config['num_tag_close'] = '</span>';

    $config['cur_tag_open'] = '<span class="current"><a href="#">';
    $config['cur_tag_close'] = '</a></span>';

    $this->pagination->initialize($config);

    //Call the model function here to get the result, 
    $data['artworks'] = $this->Artwork_model->get_artworks($language_id, $limit, $offset, $artwork_id);

    $this->template->write('title', 'Artwork : Manage Artwork');
    $this->template->write_view('content', 'artwork/index', $data);
    $this->template->render();
}

这是模型中具有多个连接的查询示例

public function get_artworks($language_id = 1, $limit = 10, $offset = 0, $arwork_id = null)
    {        
        $this->db->select('a.id, a.price, a.is_shop, at.title,at.status,at.date_added,ats.name as artist_name');
        $this->db->from('artworks a');
        $this->db->join('artwork_translations at', 'a.id = at.artwork_id');
        $this->db->join('artists ats', 'a.artist_id = ats.id');
        $this->db->where('at.language_id', $language_id);
        if(!is_null($arwork_id) && !empty($arwork_id) && $arwork_id != 'all')
        {
            $this->db->where('a.id =', $arwork_id);
        }
        $this->db->order_by('a.id DESC');
        $this->db->limit($limit, $offset);

        $artworks = $this->db->get();

        return $artworks->result();
    }

在视图中

<?= $this->pagination->create_links(); ?>
于 2013-02-18T06:19:16.713 回答
0

只需使用 PHP 函数 array_merge

<?php $beginning = 'foo'; $end = array(1 => 'bar');
$result = array_merge((array)$beginning, (array)$end);
$this->load->view('view.php', $result);
?>

并根据使用的数组的键进行提取。这真的很简单&工作

于 2013-02-18T05:57:08.497 回答
0

分页类不关心数据源是如何构造的，只要你把它想要的数据结果对象交给它。因此，您只需将限制和偏移量传递到数据查询中，或者提取所有数据并在之后对其进行切片。

但是，我真的不明白您是如何考虑将这些不同的数据位组合成一个结果来显示的——您是要显示所有类别，然后对产品进行分页吗？如果是这样，您设置不正确

于 2013-02-18T00:37:10.287 回答