javascript - 如何检测窗口外的 MouseUp 事件？

Question

我正在寻找 jQuery 解决方案来检测mouseup窗口外。也就是说，在鼠标在窗口内被按下后，在仍然向下的同时将鼠标拖到外面，然后在外面释放，这就是事件应该触发的时间。

我试过document.mouseup = function() {}了，它没有帮助。我尝试按照此处的示例进行操作，但无法正确理解（我什至留下了评论寻求帮助，但还没有帮助..:()

Answer 1

I have a website that uses this event and it works as you described:

$(window).on('mouseup', function(){
   //your code here
});

Note: only tested in jQuery 1.8.3, but it should work in 1.9

jsFiddle confirms. Works in jQuery 1.9.1 and 2 beta: http://jsfiddle.net/udRNx/1/

In case you didn't know, this piece of code must be placed in either $(document).ready(fn) or $(window).onload(fn).