只是为了解释发生了什么，我将一个排序的链表输入到一个方法中。在这个链表中是包含字符串的节点。节点包含字符串和后面会提到的 2 个计数器。这些字符串是字母数字的，可以重复。最后，我想输出一个链表，其中每个节点包含一个唯一的单词（全部小写），出现次数的计数器，以及单词不同方差的计数器（方差是由某些字符的不同大小写引起的）。我相信它合乎逻辑；但是，我遇到了分段错误。
提前致谢！
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
typedef int bool;
#define TRUE 1
#define FALSE 0
struct Node{
char value[100];
int numOccur;
int numVariance;
struct Node *next;
};
struct Node * getFinalNodes(struct Node *head){
struct Node * curr;
struct Node * finalNode;
struct Node * ptr;
struct Node * finalCurr;
struct Node * prev;
int m = 0;
int z = 0;
char lowercase1[100];
char lowercase2[100];
curr = head; //curr = head of sorted node
finalNode = head;
ptr = finalNode;
finalCurr = finalNode;
for(m = 0; curr->value[m] != '\0'; m++){
finalNode->value[m] = tolower(curr->value[m]); //gets first word all lower-cased
}
ptr->numOccur=1; //occurance is 1
ptr->numVariance=1; //variance is 1
while(curr != NULL && curr->next != NULL){
prev = curr;
curr = curr->next;
if((strcmp(prev->value, curr->value) != 0) && (strlen(prev->value) == strlen(curr->value))){ //example: Ab vs. AB
for(z=0; curr->value[z] != '\0'; z++){ //turn prev and curr into lowercase
lowercase1[z] = tolower(prev->value[z]); //ex. Ab->ab and AB->ab
lowercase2[z] = tolower(curr->value[z]);
}
if(strcmp(lowercase1,lowercase2) == 0){ //if values are same, that means they are the same words, just different capitalizations
ptr->numOccur++;
ptr->numVariance++;
}
else{ //if values are different, then they are completely different strings and put curr.value into a new finalNode
strcpy(finalNode->value,lowercase2);
ptr->next = finalNode;
ptr = ptr->next;
ptr->numOccur = 1;
ptr->numVariance =1;
}
}
else if((strcmp(prev->value, curr->value) != 0) && (strlen(curr->value) != strlen(prev->value))){ //created arrays for prev and curr
for(z=0; curr->value[z] != '\0'; z++){ //turn prev and curr into lowercase //ex. Ab->ab and AB->ab
lowercase2[z] = tolower(curr->value[z]);
}
strcpy(finalNode->value,lowercase2);
ptr->next = finalNode;
ptr = ptr->next;
ptr->numOccur = 1;
ptr->numVariance =1;
}
else if(strcmp(prev->value, curr->value) == 0){
ptr->numOccur++;
}
}
};