oracle11g - 在下一列值中显示第一列值，直到遇到非空值

Question

我有表 part_volume 列部分，volume_1，volume_2，volume_3，volume_4，volume_5，volume_6 列。

表有如下数据：

PART      VOLUME_1 VOLUME_2 VOLUME_3 VOLUME_4 VOLUME_5 VOLUME_6               
--------- -------- -------- -------- -------- -------- --------
camera        1500        0        0        0     3000        0

我想将数据显示为

PART      VOLUME_1 VOLUME_2 VOLUME_3 VOLUME_4 VOLUME_5 VOLUME_6               
--------- -------- -------- -------- -------- -------- --------
camera        1500     1500     1500     1500     3000     3000    

我怎样才能在 oracle 中实现这一点？

谢谢并恭祝安康，

洛帕

Answer 1

所以如果当前值是，只保留先前的值0？

如果是这样：

select part,
       volume_1,
       coalesce(volume_2, volume_1) volume_2,
       coalesce(volume_3, volume_2, volume_1) volume_3,
       coalesce(volume_4, volume_3, volume_2, volume_1) volume_4,
       coalesce(volume_5, volume_4, volume_3, volume_2, volume_1) volume_5,
       coalesce(volume_6, volume_5, volume_4, volume_3, volume_2, volume_1) volume_6
  from (select part,
               volume_1,
               case volume_2 when 0 then to_number(null) else volume_2 end volume_2,
               case volume_3 when 0 then to_number(null) else volume_3 end volume_3,
               case volume_4 when 0 then to_number(null) else volume_4 end volume_4,
               case volume_5 when 0 then to_number(null) else volume_5 end volume_5,
               case volume_6 when 0 then to_number(null) else volume_6 end volume_6
          from data);

是否可能为空，如果是，规则是否与零相同？