android - PagerAdapter 类被多次调用

Question

我正在开发一个应用程序，其中有一个 ViewPager 视图，我创建了一个 PagerAdapter，它有视图，PagerAdapter 的 instanceiteItem() 方法在 create() 中被调用了两次我不知道为什么，谁能帮我这？

这是我的代码，

         View PagerView;
        MyPagerAdapter adapter;
        ViewPager pager;

            adapter = new MyPagerAdapter();     
    pager.setAdapter(adapter);
    pager.setCurrentItem(0);

public class MyPagerAdapter extends PagerAdapter {

        @Override
        public Object instantiateItem(final View collection, final int position) {
            Log.d("Inside", "Pager");
            PagerView = new View(collection.getContext());
            LayoutInflater inflater = (LayoutInflater) collection.getContext()
                    .getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            PagerView = inflater.inflate(R.layout.tablemenu, null, false);
            tbMenuDetails = (TableLayout) PagerView
                    .findViewById(R.id.Menutable1);
            scrollview = (ScrollView) PagerView.findViewById(R.id.scrollView1);
            tbMenuDetails.removeAllViews();
            removeTableRows();
            createTableLayout(position);
            String str[][] = datasource.GetSubMenuDetailsFromMenuId(MenuIdlst
                    .get(position).trim());
            Log.d("Str", "" + str.length);
            for (int i = 0; i < str.length; i++) {
                addRows(str[i][1], str[i][2], str[i][0], str[i][3], position);
                Log.d("Message", "Pos   " + position + "    SubMenuName" + str[i][2]
                        + " SubMenuId" + " " + str[i][0] + " TypeID" + "    "
                        + str[i][3]);
            }

            // View view = inflater.inflate(resId, null);
            ((ViewPager) collection).addView(PagerView, 0);

            return PagerView;
        }

        @Override
        public void destroyItem(final View arg0, final int arg1,
                final Object arg2) {
            ((ViewPager) arg0).removeView((View) arg2);

        }

        @Override
        public boolean isViewFromObject(final View arg0, final Object arg1) {
            return arg0 == ((View) arg1);

        }

        @Override
        public void finishUpdate(View arg0) {
            // TODO Auto-generated method stub

        }

        @Override
        public void restoreState(Parcelable arg0, ClassLoader arg1) {
            // TODO Auto-generated method stub

        }

        @Override
        public Parcelable saveState() {
            // TODO Auto-generated method stub
            return null;
        }

        @Override
        public void startUpdate(View arg0) {
            // TODO Auto-generated method stub

        }

        @Override
        public int getCount() {
            // TODO Auto-generated method stub
            return MenuIdlst.size();
        }

    }

请帮忙

score 5 · Accepted Answer

如果您决定使用 Fragments，请不要实现PagerAdapter. 相反，扩展FragmentPagerAdapter或FragmentStatePagerAdapter：

private class MyPagerAdapter extends FragmentStatePagerAdapter {
    public MyPagerAdapter(FragmentManager fm) {
        super(fm);
    }

    @Override
    public int getCount() {
        return NUMBER_OF_PAGES_IN_PAGER;
    }

    @Override
    public Fragment getItem(int position) {
        // Implement the static method newInstance in MyFragment.java yourself.
        // It should return you a brand new instance of MyFragment, basically using
        // the code you had in your original instantiateItem method.
        return MyFragment.newInstance(position, ... etc ...); 
    }
}

然后在您的活动中：

myPagerAdapter = new MyPagerAdapter(getFragmentManager());
// or myPagerAdapter = new MyPagerAdapter(getSupportFragmentManager());
myViewPager.setAdapter(myPagerAdapter);

要获取有关如何使用 Fragments 和 ViewPagers 的更多信息： https ://developer.android.com/reference/android/app/Fragment.html https://developer.android.com/reference/android/support/v4/view /ViewPager.html https://developer.android.com/reference/android/support/v4/app/FragmentStatePagerAdapter.html

score 4 · Accepted Answer

默认情况下，ViewPager 在当前页面（如果有）之前/之前预加载一页。你没有说它是否被要求相同或不同的位置。

score 3 · Accepted Answer

ViewPager.setOffscreenpageLimit(int)的最小值为 1。您可以从ViewPager 的源代码中看到：

private static final int DEFAULT_OFFSCREEN_PAGES = 1;

...

/**
     * Set the number of pages that should be retained to either side of the
     * current page in the view hierarchy in an idle state. Pages beyond this
     * limit will be recreated from the adapter when needed.
     *
     * <p>This is offered as an optimization. If you know in advance the number
     * of pages you will need to support or have lazy-loading mechanisms in place
     * on your pages, tweaking this setting can have benefits in perceived smoothness
     * of paging animations and interaction. If you have a small number of pages (3-4)
     * that you can keep active all at once, less time will be spent in layout for
     * newly created view subtrees as the user pages back and forth.</p>
     *
     * <p>You should keep this limit low, especially if your pages have complex layouts.
     * This setting defaults to 1.</p>
     *
     * @param limit How many pages will be kept offscreen in an idle state.
     */
    public void setOffscreenPageLimit(int limit) {
        if (limit < DEFAULT_OFFSCREEN_PAGES) {
            Log.w(TAG, "Requested offscreen page limit " + limit + " too small; defaulting to " +
                    DEFAULT_OFFSCREEN_PAGES);
            limit = DEFAULT_OFFSCREEN_PAGES;
        }
        if (limit != mOffscreenPageLimit) {
            mOffscreenPageLimit = limit;
            populate();
        }
    }

如果您尝试将其设置为零，您应该会在 Logcat 中看到警告。

The lower limit is 1 for a very good reason. The adjacent page needs to be already loaded when you scroll the pager - otherwise you will not see anything for the next page. If you manage to force the offscreen page limit to zero, you would probably just see a black, empty page as you scroll from the first page to the second. If you have a particular problem with both the first and second pages being created at the beginning, then try to target and fix that.

score 2 · Accepted Answer

为寻呼机中的每个视图使用片段。

将下面的代码写onCreate()在FragmentActivity.

List<Fragment> fragments = new Vector<Fragment>();

//for each fragment you want to add to the pager
Bundle page = new Bundle();
page.putString("url", url);
fragments.add(Fragment.instantiate(this,MyFragment.class.getName(),page));

//after adding all the fragments write the below lines

this.mPagerAdapter  = new PagerAdapter(super.getSupportFragmentManager(), fragments);

mPager.setAdapter(this.mPagerAdapter);

示例片段定义：

public class MyFragment extends Fragment {


public static MyFragment newInstance(String imageUrl) {

final MyFragment mf = new MyFragment ();

    final Bundle args = new Bundle();
    args.putString("somedata", "somedata");
    mf.setArguments(args);

    return mf;
}

public MyFragment() {}

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    String data = getArguments().getString("somedata");
}

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    // Inflate and locate the main ImageView
    final View v = inflater.inflate(R.layout.my_fragment_view, container, false);
    //... 
    return v;
}

每当我需要使用ViewPager. 希望这可以帮助。我无法从您提供的信息中弄清楚为什么您的实例化方法被调用了两次。

score -1 · Accepted Answer

There change to make that is essential for the isViewFromObject() method. It is very important and in it's documentation it is said that "This method is required for a PagerAdapter to function properly."

@Override
public boolean isViewFromObject(View view, Object object) {
    if(object != null){
        return ((Fragment)object).getView() == view;
    }else{
        return false;
    }
}

You can look here.

android - PagerAdapter 类被多次调用

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