powershell - Powershell 按多个字段分组

Question

以下脚本将返回两列。是否可以在显示文件名的列前面添加另一列？

ls | select -First 10 |
% { 
    cat $_ | Select-String `, -AllMatches | 
        Select-Object LineNumber, @{n="Count"; e={$_.Matches.Count}} | 
        Group-Object Count | 
        % {
            New-Object psobject -Property @{
                "Count" = $_.Name
                "LineNumbers" = ($_.Group | Select-Object -ExpandProperty LineNumber) 
            }
        }
}

计算行号                            
----- ------------                            
77 {1, 2, 3, 4...}                        
78 {7, 15, 22, 43...}                     
79 {16、32、37、90...}                    
77 {1, 2, 3, 4...}                        
78 {7, 15, 22, 43...}                     
79 {16、32、37、90...}                    
77 {1, 2, 3, 4...}                        
78 {7, 15, 22, 43...}                     
79 {16、32、37、90...}                    
77 {1, 2, 3, 4...}                        
78 {7, 15, 22, 43...}                     
79 {16、32、37、90...}                    
77 {1, 2, 3, 4...}                        
78 {7, 15, 22, 43...}                     
79 {16、32、37、90...}                    
77 {1, 2, 3, 4...}                        
78 {7, 15, 22, 43...}                     
79 {16、32、37、90...}                    
89 {1, 2, 3, 4...}                        
89 {1, 2, 3, 4...}                        
89 {1, 2, 3, 4...}                        
89 {1, 2, 3, 4...}                        

Answer 1

试试这个（未经测试）：

ls | select -First 10 |
% {
    $filename = $_.Name 
    cat $_ | Select-String `, -AllMatches | 
        Select-Object LineNumber, @{n="Count"; e={$_.Matches.Count}} | 
        Group-Object Count | 
        % {
            New-Object psobject -Property @{
                "FileName" = $filename
                "Count" = $_.Name
                "LineNumbers" = ($_.Group | Select-Object -ExpandProperty LineNumber) 
            }
        }
}

如果您想要文件路径而不仅仅是文件名，请将第 3 行更改为$filename = $_.FullName