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我正在尝试以以下格式构建 XML（我们的提供程序没有 XSD）：

<Submission>
<Office Account="ACCOUNT">
    <schedule submissionPeriod="" areaOfLaw="" scheduleNum="abc">
        <outcome matterType="A:B">
            <outcomeItem Name="CASE_START_DATE">DATA</outcomeItem>
            <outcomeItem Name="CASE_ID">DATA</outcomeItem>
        </outcome>
        <outcome matterType="C:D">
            <outcomeItem Name="CASE_START_DATE">DATA</outcomeItem>
            <outcomeItem Name="CASE_ID">DATA</outcomeItem>
        </outcome>
    </schedule>
    <schedule submissionPeriod="" areaOfLaw="" scheduleNum="def">
        <outcome matterType="E:F">
            <outcomeItem Name="CASE_START_DATE">DATA</outcomeItem>
            <outcomeItem Name="CASE_ID">DATA</outcomeItem>
        </outcome>
    </schedule>
</Office>
<Office Account="ACCOUNT2">
    <schedule submissionPeriod="" areaOfLaw="" scheduleNum="ghi">
        <outcome matterType="A:B">
            <outcomeItem Name="CASE_START_DATE">DATA</outcomeItem>
            <outcomeItem Name="CASE_ID">DATA</outcomeItem>
        </outcome>
    </schedule>
</Office>

我有以下 SQL

SELECT  supplier_no AS 'Office/@Account' ,
    UPPER(LEFT(DATENAME(MM, GETDATE()), 3)) + '-' + DATENAME(YYYY,
                                                          GETDATE()) AS 'Office/schedule/@submissionPeriod' ,
    'LEGAL HELP' AS 'Office/schedule/@areaOfLaw' ,
    supplier_no + '/CIVIL' AS 'Office/schedule/@scheduleNum' ,
    ClaimsTable.mattype1_code + ':' + ClaimsTable.mattype2_code AS 'Office/schedule/outcome/@matterType' , 
    (SELECT * FROM ( 

                  SELECT 'CASE_START_DATE' AS 'outcomeItem/@Name', 'DATA' AS 'outcomeItem' UNION ALL
                  SELECT 'CASE_ID' AS 'outcomeItem/@Name',  'DATA' AS 'outcomeItem'

                ) OutcomeItems FOR XML PATH(''), TYPE) AS 'Office/schedule/outcome'

FROM    ContractsTable
    LEFT OUTER JOIN ClaimsTable ON ContractsTable.contract_no = ClaimsTable.contract_no
WHERE   ClaimsTable.compno = 2
    AND ClaimsTable.submitted_period = 0
FOR     XML PATH('Submission') ,
        TYPE

生成以下 XML

<Submission>
  <Office Account="MHESUPPLIE">
<schedule submissionPeriod="FEB-2013" areaOfLaw="LEGAL HELP" scheduleNum="MHESUPPLIE/CIVIL">
  <outcome matterType="MHNS:MOUT">
    <outcomeItem Name="CASE_START_DATE">13/02/2013</outcomeItem>
    <outcomeItem Name="CASE_ID">001</outcomeItem>
  </outcome>
</schedule>
  </Office>
</Submission>
<Submission>
  <Office Account="MHESUPPLIE">
<schedule submissionPeriod="FEB-2013" areaOfLaw="LEGAL HELP" scheduleNum="MHESUPPLIE/CIVIL">
  <outcome matterType="MHAS:MGUA">
    <outcomeItem Name="CASE_START_DATE">14/02/2013</outcomeItem>
    <outcomeItem Name="CASE_ID">001</outcomeItem>
  </outcome>
</schedule>
  </Office>
</Submission>

显然，输出 XML 有多个无效的根节点。我试图找到一种方法将结果组合在一起以实现我需要的 XML 类型。关于如何在 SQL Server 2005+ 上实现这一点有什么想法吗？

4

1 回答 1

1

我简化了你的查询。假设您的查询如下所示：

SELECT STR(X) AS [office/schedule]
FROM (VALUES(1),(2)) AS CompleQuery(x)
FOR XML PATH('Submission'),TYPE;

这会产生：

<Submission><office><schedule> 1</schedule></office></Submission><Submission><office><schedule> 2</schedule></office></Submission>

要将两个 office 标签合并到一个提交中，请改用：

SELECT (
SELECT STR(X) AS [office/schedule]
FROM (VALUES(1),(2)) AS CompleQuery(x)
FOR XML PATH(''),TYPE
  )
FOR XML PATH('Submission'),TYPE;

因此，在您的查询中更改PATH('Submission')为PATH('')，然后将其包装到另一个SELECT ... FOR XML PATH('Submission'),TYPE;

结果：

<Submission><office><schedule> 1</schedule></office><office><schedule> 2</schedule></office></Submission>
于 2013-02-14T16:34:15.570 回答