D3中是否有等效的气泡树实现?在我提供的链接中,气泡树是用 RaphaelJS 和 jQuery 实现的。
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3910 次
3 回答
1
你的问题的直接答案是否定的。
使用https://github.com/okfn/bubbletree/tree/master/build上的资源、您已经知道的信息以及http://d3js.org/上提供的信息以及通过 D3 在 GitHub 上的文档,您应该能够为 D3 变出你自己的泡泡树!
这是我很久以前用来可视化二叉树数据的一段 JavaScript:
var updateVisual;
updateVisual = function() {
var drawTree, out;
drawTree = function(out, node) {
var col, gray, i, line, lineElt, lines, sub, _results, _results1;
if (node.lines) {
out.appendChild(document.createElement("div")).innerHTML = "<b>leaf</b>: " + node.lines.length + " lines, " + Math.round(node.height) + " px";
lines = out.appendChild(document.createElement("div"));
lines.style.lineHeight = "6px";
lines.style.marginLeft = "10px";
i = 0;
_results = [];
while (i < node.lines.length) {
line = node.lines[i];
lineElt = lines.appendChild(document.createElement("div"));
lineElt.className = "lineblock";
gray = Math.min(line.text.length * 3, 230);
col = gray.toString(16);
if (col.length === 1) col = "0" + col;
lineElt.style.background = "#" + col + col + col;
console.log(line.height, line);
lineElt.style.width = Math.max(Math.round(line.height / 3), 1) + "px";
_results.push(i++);
}
return _results;
} else {
out.appendChild(document.createElement("div")).innerHTML = "<b>node</b>: " + node.size + " lines, " + Math.round(node.height) + " px";
sub = out.appendChild(document.createElement("div"));
sub.style.paddingLeft = "20px";
i = 0;
_results1 = [];
while (i < node.children.length) {
drawTree(sub, node.children[i]);
_results1.push(++i);
}
return _results1;
}
};
out = document.getElementById("btree-view");
out.innerHTML = "";
return drawTree(out, editor.getDoc());
};
只需插入一些圆形元素并对其进行一些操作以在圆形庄园中进行样式设置,您就应该拥有一个很好的程序集!
于 2013-08-08T10:42:56.923 回答
1
Here you go. I didn't add the text or decorations, but it's the meat and potatoes:
function bubbleChart(config) {
var aspectRatio = 1,
margin = { top: 0, right: 0, bottom: 0, left: 0 },
radiusScale = d3.scale.sqrt(),
scan = function(f, data, a) {
a = a === undefined ? 0 : a;
var results = [a];
data.forEach(function(d, i) {
a = f(a, d);
results.push(a);
});
return results;
},
colorScale = d3.scale.category20(),
result = function(selection) {
selection.each(function(data) {
var outerWidth = $(this).width(),
outerHeight = outerWidth / aspectRatio,
width = outerWidth - margin.left - margin.right,
height = outerHeight - margin.top - margin.bottom,
smallestDimension = Math.min(width, height),
sum = data[1].reduce(function(a, d) {
return a + d[1];
}, 0),
radiusFractions = data[1].map(function(d) {
return Math.sqrt(d[1] / sum);
}),
radiusNormalSum = radiusFractions.reduce(function(a, d) {
return a + d;
}, 0),
scanned = scan(function(a, d) {
return a + d;
}, radiusFractions.map(function(d) {
return d / radiusNormalSum;
}), 0);
radiusScale.domain([0, sum]).range([0, smallestDimension / 6]);
var svg = d3.select(this).selectAll('svg').data([data]),
svgEnter = svg.enter().append('svg');
svg.attr('width', outerWidth).attr('height', outerHeight);
var gEnter = svgEnter.append('g'),
g = svg.select('g').attr('transform', 'translate(' + margin.left + ' ' + margin.top + ')'),
circleRing = g.selectAll('circle.ring').data(data[1]),
circleRingEnter = circleRing.enter().append('circle').attr('class', 'ring');
circleRing.attr('cx', function(d, i) {
return smallestDimension / 3 * Math.cos(2 * Math.PI * (scanned[i] + scanned[i + 1]) / 2) + width / 2;
}).attr('cy', function(d, i) {
return smallestDimension / 3 * Math.sin(2 * Math.PI * (scanned[i] + scanned[i + 1]) / 2) + height / 2;
}).attr('r', function(d) {
return radiusScale(d[1]);
}).style('fill', function(d) {
return colorScale(d[0]);
});
var circleMain = g.selectAll('circle#main').data([data[0]]),
circleMainEnter = circleMain.enter().append('circle').attr('id', 'main');
circleMain.attr('cx', width / 2).attr('cy', height / 2).attr('r', radiusScale(sum)).style('fill', function(d) {
return colorScale(d);
});
});
};
result.aspectRatio = function(value) {
if(value === undefined) return aspectRatio;
aspectRatio = value;
return result;
};
result.margin = function(value) {
if(value === undefined) return margin;
margin = value;
return result;
};
return result;
}
var myBubbleChart = bubbleChart().margin({
top: 1,
right: 1,
bottom : 1,
left: 1
});
var data = ['Random Names, Random Amounts', [['Immanuel', .4], ['Pascal', 42.9], ['Marisa', 3.3], ['Hadumod', 4.5], ['Folker', 3.2], ['Theo', 4.7], ['Barnabas', 1.0], ['Lysann', 11.1], ['Julia', .7], ['Burgis', 28.2]]];
d3.select('#here').datum(data).call(myBubbleChart);
<div class="container">
<div class="row">
<div class="col-xs-12">
<div id="here"></div>
</div>
</div>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>
于 2016-08-09T17:33:09.547 回答
0
您可以使用包布局,基本上您可以将您想要的任何数据绑定到图表中的形状和自定义参数,以便它们相互尊重。另一种选择是力布局。
于 2015-05-21T10:31:59.993 回答