1

我这里有个问题..

假设我有这张桌子......

waktu               |   tglTransaksiJual   | nominal   | ongkir    | STATUS    | idUser
---------------------------------------------------------------------------------------
2013-02-01 00:00:00 | 2013-01-29 15:00:00  | 10000     | 10000     | APPROVED  | 1
0000-00-00 00:00:00 | 2013-02-02 15:00:00  | 20000     | 0         | DONE      | 2
0000-00-00 00:00:00 | 2013-02-02 15:00:00  | 10000     | 5000      | DONE      | 2
2013-02-03 00:00:00 | 2013-02-01 15:00:00  | 20000     | 0         | APPROVED  | 3

并且我使用这个查询

SELECT DISTINCT(date(IF(waktu = '0000-00-00 00:00:00', tglTransaksiJual, waktu))) AS thedate, SUM( nominal+ongkir ) AS total
        FROM transaksijual
        WHERE IF(waktu = '0000-00-00 00:00:00', tglTransaksiJual, waktu) BETWEEN '2013-02-01' AND '2013-02-05' AND status LIKE 'DONE%' AND idUser LIKE '2%'    
        GROUP BY thedate
        ORDER BY thedate ASC

但我得到的结果是

thedate    | total
-------------------
2013-02-01 | 30000

我想要的是这样的

thedate    | total
------------------
2013-02-01 | 0
2013-02-02 | 35000
2013-02-03 | 0

我怎样才能做到这一点？？那可能吗？？所以结论是..当没有数据时，我想获取 0 值并获取行...

4

1 回答 1

1

删除WHERE条件并将SUM列更新为仅在满足条件时求和：

SUM(IF(status = 'DONE' AND idUser = '2', nominal + ongkir, 0))
于 2013-02-14T04:51:07.340 回答