2

这是我的桌子现在的样子：

如您所见，有多个记录，例如 XRAY。我想做的是列举那些像 1st Xray 2nd Xray 3rd Xray

或任何类型的枚举。

顺便说一下我当前表的查询

"SELECT
             `incurredcharges`.`procedure_no`,
  `c`.`procedure`

FROM
  incurredcharges
  INNER JOIN (
    SELECT `procedure`, `procedure_no` FROM `charges`
    UNION ALL
    SELECT `confinement`, `procedure_no` FROM `confinement`
    UNION ALL
    SELECT `service`, `procedure_no` FROM `ultrasound`
  ) c ON `incurredcharges`.`procedure_no` = c.`procedure_no`
WHERE `incurredcharges`.`patient_no` = '$id'";
4

1 回答 1

0

虽然我不知道如何添加“1st”、“2nd”等，但您可以添加 1、2 等。这是一个示例：

SELECT
  CONCAT(CASE WHEN cnt > 1 THEN CONCAT(RN,'-') ELSE '' END, t.Proc) Proc
FROM
  (
    SELECT
      @curRow:=CASE WHEN @prevRow = a.Proc THEN @curRow+1 ELSE 1 END AS rn,
      a.Proc,
      @prevRow:=Proc grp
    FROM (
         SELECT Proc FROM Procedures ORDER BY Proc
      ) a JOIN (SELECT @curRow:=0) r
  ) t JOIN
  (
    SELECT Proc, COUNT(Proc) cnt 
    FROM Procedures 
    GROUP BY Proc
  ) c ON t.proc = c.proc

这是SQL Fiddle。

基本上，您需要将您的程序分组在一起，为每个组提供一个行号。对于那些超过一个的记录，在前面加上行号。

- -编辑 - -

鉴于您的评论，您的查询只需放在主 FROM 中（靠近中间），然后您需要将 procno 带到每个 select 语句中。这是一些应该非常接近的东西，尽管未经测试：

SELECT
  procno,
  CONCAT(CASE WHEN cnt > 1 THEN CONCAT(RN,'-') ELSE '' END, t.Proc) Proc
FROM
  (
    SELECT
      @curRow:=CASE WHEN @prevRow = a.Proc THEN @curRow+1 ELSE 1 END AS rn,
      a.Proc,
      a.Procno,
      @prevRow:=Proc grp
    FROM (    
          SELECT
            `incurredcharges`.`procedure_no` procno,
            `c`.`procedure` proc
          FROM
            incurredcharges
            INNER JOIN (
              SELECT `procedure`, `procedure_no` FROM `charges`
              UNION ALL
              SELECT `confinement`, `procedure_no` FROM `confinement`
              UNION ALL
              SELECT `service`, `procedure_no` FROM `ultrasound`
            ) c ON `incurredcharges`.`procedure_no` = c.`procedure_no`
          WHERE `incurredcharges`.`patient_no` = '$id'
          ORDER BY `c`.`procedure`
      ) a 
          JOIN (SELECT @curRow:=0) r
  ) t JOIN
  (
          SELECT
            `incurredcharges`.`procedure_no` procno,
            `c`.`procedure` proc, Count(*) cnt
          FROM
            incurredcharges
            INNER JOIN (
              SELECT `procedure`, `procedure_no` FROM `charges`
              UNION ALL
              SELECT `confinement`, `procedure_no` FROM `confinement`
              UNION ALL
              SELECT `service`, `procedure_no` FROM `ultrasound`
            ) c ON `incurredcharges`.`procedure_no` = c.`procedure_no`
          WHERE `incurredcharges`.`patient_no` = '$id'
          GROUP BY `incurredcharges`.`procedure_no`,
            `c`.`procedure`
  ) c ON t.proc = c.proc

祝你好运。

于 2013-02-13T19:45:12.443 回答