scala - 为什么在Scala中使用参数调用大写时会调用charAt

Question

scala> "Foo".capitalize(2)    
res18: Char = o

Answer 1

复制自StringLike 特征文档：

def capitalize: String
Returns this string with first character converted to upper case

你实际上在做的是

“Foo”.capitalize.apply(2)

文档再次：

def apply(n: Int): Char
Return element at index n