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我在存储过程中创建了带有 52600 条记录的临时表，我想迭代临时表并为每一行更新一列。

在这里，我有两个cursors用于临时表，第二个用于其他表，例如 table2，它有三行，我必须从临时表中取出 1 行并遍历 table2 并进行比较，如果找到匹配，我正在更新临时表中的列。

这个过程大约需要 500 秒的时间，stored procedure使用游标和循环是好还是在代码中好？

DELIMITER $$

CREATE DEFINER=`root`@`localhost` PROCEDURE `sp_repaymentDelay`()
BEGIN
    drop table if exists loan_repayed_temp;
    create temporary table loan_repayed_temp ( l_id int primary key, loan_Id int, installmentNo int,date_Diff int,interval_id int default 0);

insert into loan_repayed_temp (l_id,loan_Id,installmentNo,date_Diff) 

     select  lrs.id ,lrs.loan_profile_id ,lrs.installment_number , datediff(curdate(), lrs.estimated_payment_date) from 
 loanTable lp inner join loanrepaymentschedule lrs on lp.id = lrs.loan_profile_id and lp.state = 'REPAYMENT_IN_PROGRESS'
 left join repayments r on lrs.loan_profile_id = r.loan_profile_id and r.repayment_number = lrs.installment_number 
 where r.loan_profile_id is null and lrs.estimated_payment_date < NOW()  

;

    BEGIN
        declare done int default false;

        declare lid, loanId, installmentNo , dateDiff int;
        declare cursor2 cursor for select id, interval_range_min, interval_range_max from delay_interval;
        declare cursor1 cursor for select l_id,loan_Id, installmentNo,date_Diff from loan_repayed_temp;

        declare continue handler for not found set done = true;

       open cursor1;

            cursor1_loop : loop

                fetch cursor1 into lid, loanId, installmentNo, dateDiff;

                IF done THEN
                LEAVE cursor1_loop;
                END IF;


          --    delay interval comparision --

                BEGIN
                    declare i , min ,max int;
                    declare done2 int default false;
                    declare continue handler for not found set done2 = true;

                    open cursor2;

                    cursor2_loop: loop

                            fetch cursor2 into i, min, max;

                            IF done2 THEN
                            LEAVE cursor2_loop;
                            end IF;



                                if dateDiff >= min and dateDiff <= max then



                            --    insert into datedemo values(dateDiff,loanId,i);


                                 update loan_repayed_temp set interval_id = i where l_id = lid; 

                                    leave cursor2_loop;

                                end if; 



                        end loop cursor2_loop; 

                    close cursor2;
                END; 

                -- --



                end loop cursor1_loop;



        close cursor1;

    END; 



    drop table  loan_repayed_temp;
END
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1 回答 1

0

如果我正确理解了您的光标，您将遍历临时表中的所有记录并查看 date_diff 字段是否介于 delay_interval 表的最小值和最大值之间。如果是这样，我认为这将以相同的方式工作，并且应该更快：

UPDATE loan_repayed_temp l
    INNER JOIN delay_interval d
        ON l.date_Diff >= d.interval_range_min
            AND l.date_Diff <= interval_range_max
SET l.interval_id = d.id

这是一个示例SQL Fiddle。如果我误解了，请告诉我。

祝你好运。

于 2013-02-13T05:21:58.593 回答