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我有这段代码,我正在尝试传递this.thecost给该public void click()方法,但它看起来不起作用,因为我在单击 paypal 按钮时收到“Paymnet Failed”。

我做错了什么?

顺便说一句,你怎么称呼private {}, private void {}- 所有那些看起来像 function() 的东西?

private void initUI(int theprice) {

        launchPayPalButton = mPayPal.getCheckoutButton(this, 
                PayPal.BUTTON_278x43, CheckoutButton.TEXT_PAY);

        LinearLayout.LayoutParams params = new
                LinearLayout.LayoutParams(LayoutParams.WRAP_CONTENT, 
                        LayoutParams.WRAP_CONTENT);

        params.bottomMargin = theprice;
        this.thecost = theprice;

        launchPayPalButton.setLayoutParams(params);
        launchPayPalButton.setOnClickListener(this);

        ((LinearLayout)findViewById(R.id.main_layout2)).addView(launchPayPalButton);
    }

    public void onClick(View v) {
        payWithPaypal(this.thecost);
    }


private void payWithPaypal(Integer gg) {
        PayPalPayment newPayment = new PayPalPayment();
        BigDecimal bigDecimal=new BigDecimal(gg);
        newPayment.setSubtotal(bigDecimal);
        newPayment.setCurrencyType(Currency.getInstance(Locale.US));
        newPayment.setRecipient("email@hotmail.com");
        newPayment.setMerchantName("My Merchant");
        Intent paypalIntent = PayPal.getInstance().checkout(newPayment, this);
        this.startActivityForResult(paypalIntent, 1);
    }

    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);

        switch(resultCode) {
        case Activity.RESULT_OK:
            String payKey = data.getStringExtra(PayPalActivity.EXTRA_PAY_KEY);
            data.getStringExtra(PayPalActivity.EXTRA_PAY_KEY);
            Toast.makeText(this,"Paymnet Successful",Toast.LENGTH_LONG).show();
            break;
        case Activity.RESULT_CANCELED:
            Toast.makeText(this,"Paymnet Cancel",Toast.LENGTH_LONG).show();
            break;
        case PayPalActivity.RESULT_FAILURE:
            Toast.makeText(this,"Paymnet Failed",Toast.LENGTH_LONG).show();
            String errorID = 
            data.getStringExtra(PayPalActivity.EXTRA_ERROR_ID);
            String errorMessage = 
                    data.getStringExtra(PayPalActivity.EXTRA_ERROR_MESSAGE);
            break;

        }

编辑:我在 oncreate 方法调用 initUI()

再次编辑:我将全局变量更改为“double”,因为价格通常有小数位。现在我试着为这个值敬酒,我更清楚地看到了错误。Toast 显示一条消息,表明传递的值为“0.0”。因此,出现“付款失败”和无效付款的错误。

int eprice;
    double thecost;    
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.detail);

    //Data mSource = new Data;
    Intent myLocalIntent = getIntent();
    Bundle myBundle = myLocalIntent.getExtras();



    eprice = myBundle.getInt("eprice");
    String epricetxt = myBundle.getString("eprice");

    Adapter mAdapter = new Adapter(this, mSource);
    //details = (Data) mAdapter.getItem(pos);





    TextView theprice = (TextView) findViewById(R.id.priceTxt);
    theprice.setText("Price: $" + epricetxt);





    this.setCost(eprice);
    this.thecost = eprice;



    //Paypal
    mPayPal=PayPal.initWithAppID(this,Constants.PAYPAL_APP_ID,PayPal.ENV_SANDBOX);

    initUI(eprice);

}

private void initUI(int theprice) {

        launchPayPalButton = mPayPal.getCheckoutButton(this, 
                PayPal.BUTTON_278x43, CheckoutButton.TEXT_PAY);

        LinearLayout.LayoutParams params = new
                LinearLayout.LayoutParams(LayoutParams.WRAP_CONTENT, 
                        LayoutParams.WRAP_CONTENT);

        params.bottomMargin = theprice;
        this.thecost = theprice;
        launchPayPalButton.setLayoutParams(params);
        launchPayPalButton.setOnClickListener(this);

        ((LinearLayout)findViewById(R.id.main_layout2)).addView(launchPayPalButton);
    }

    public void onClick(View v) {
        //
        payWithPaypal(getCost());
    }

    public void setCost(int cost) {
        this.thecost = cost;
    }

    public double getCost() {
        return this.thecost;
    }


    private void payWithPaypal(Double gg) {
        PayPalPayment newPayment = new PayPalPayment();
        Toast.makeText(getApplicationContext(),gg.toString(), Toast.LENGTH_LONG).show();
        BigDecimal bigDecimal=new BigDecimal(gg);
        newPayment.setSubtotal(bigDecimal);
        newPayment.setCurrencyType(Currency.getInstance(Locale.US));
        newPayment.setRecipient("email@hotmail.com");
        newPayment.setMerchantName("My Merchant");
        Intent paypalIntent = PayPal.getInstance().checkout(newPayment, this);
        this.startActivityForResult(paypalIntent, 1);
    }
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2 回答 2

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我们没有足够的信息来告诉您这里出了什么问题。出于某种原因,PayPal API 返回了失败状态代码。也许你没有互联网连接?

检查您在此行中检索到的错误消息字符串的值:

String errorMessage = data.getStringExtra(PayPalActivity.EXTRA_ERROR_MESSAGE);

您可以使用调试器对其进行检查,也可以使用 Logger 类中的 Log.e 函数将其记录到 Logcat 以便您阅读。

至于你的第二个问题:

顺便说一句,你怎么称呼 private {}、private void {} - 所有那些看起来像 function() 的东西?

在 Java 中,那些“看起来像函数的东西”被称为方法。

编辑:好的,既然您已经向我们展示了您的 onCreate 方法,我可以看到您在哪里获得最终传递给 onInit 的值:

eprice = myBundle.getInt("eprice");

这样做意味着您将先前保存在捆绑包中的值onSaveInstanceState(Bundle)

是你做的吗?第一次启动 Activity 时,它是如何获取值的?

于 2013-02-13T02:52:00.170 回答
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使用我最新的代码,我不知道为什么我的 eprice 不起作用。但我有替代解决方案。我需要做的就是改变

initUI(eprice);

initUI(Double.valueOf(epricetxt));

于 2013-02-14T01:05:24.303 回答