1

我们的任务是编写一个代码，它会从 0 到 100 猜测一个秘密数字。这是我的一段代码：

low = 0
mid = 50
high = 100
secretnum = "Is your secret number " + str(mid) + "?"
print"Please think of a number between 0 and 100!"
print secretnum
herp = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. ")
while herp != 'c':
    if herp == 'h':
        high = mid
        mid = int((mid + low)/2)
    elif herp == 'l':
        low = mid
        mid = int((mid + high)/2)
    else:
        print"Sorry, I did not understand your input."
    print secretnum
    herp = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. ")
if herp == 'c':
    print "Game over. Your secret number was: " + str(mid)

这是输出：

Is your secret number 50?
Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. h
Is your secret number 50?
Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. l
Is your secret number 50?
Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. c
Game over. Your secret number was: 37
4

8 回答 8

2

对于错误将其更改为：

print "Game over. Your secret number was:",mid

对于一遍又一遍地输出 50，print secretnum在 while 中更改为：

print "Is your secret number " + str(mid) + "?"

当您secretnum="Is your secret number " + str(mid) + "?"在开头设置时，它会创建一个字符串，一个与 mid 完全分开的字符串。因此，如果您更改 mid，则不会在字符串中看到更改。

Python 字符串是不可变的，这意味着一旦创建，它们就完成了。您无法更改字符串的内容，除非完全重新制作它。什么str(mid)是创建一个字符串表示mid。在这种情况下，字符串"50"被创建并放入字符串中，永远不会被修改。str(mid)因此，当您显示一个字符串时，您需要通过再次调用来确保它显示的是最新值。

于 2013-02-13T01:42:16.577 回答
2

正如 Raufio 所指出的，Python 字符串是不可变的。要解决一遍又一遍重复 50 的问题，您需要在打印出问题时再次调用 str(mid)。例如：

low = 0
mid = 50
high = 100
secretnum = "Is your secret number: " 
print"Please think of a number between 0 and 100!"
print secretnum + str(mid) + "?"
herp = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. ")
while herp != 'c':
    if herp == 'h':
        high = mid
        mid = int((mid + low)/2)
    elif herp == 'l':
        low = mid
        mid = int((mid + high)/2)
    else:
        print"Sorry, I did not understand your input."
    print secretnum + str(mid) + "?"
    herp = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. ")
if herp == 'c':
    print "Game over. Your secret number was:", mid
于 2013-02-13T02:01:47.783 回答
1

在最后一行中，您只需输入：

print "Game over. Your secret number was: " + str(mid)

这是因为 python 想要确保你真的知道你在做什么——将两个字符串加在一起，而不是一个 int 和一个字符串——这是被禁止的。str() 函数只是将您给它的任何内容更改为字符串。关于您的语义问题，我认为此版本的代码具有预期的行为：

low = 0  
mid = 50  
high = 100  
print "Please think of a number between 0 and 100!"  
herp = 50  
while herp != 'c':  
    print "Is your secret number " + str(mid) + "?"
    herp = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is to low. Enter 'c' to indicate the guess is correct")   
    if herp == 'h':  
        high = mid  
        mid = int((mid + low)/2)  
    elif herp == 'l':  
        low = mid  
        mid = int((mid + high)/2)  
    else:  
        print"Sorry, I did not understand your input."  
if herp == 'c':  
    print "Game over. Your secret number was: " + str(mid)
于 2013-02-13T01:47:58.567 回答
0

更改第 20 行

print "Game over. Your secret number was: " + mid

到

print "Game over. Your secret number was: ", mid

或者

print "Game over. Your secret number was: " + str(mid)

于 2013-02-13T01:42:30.330 回答
0

在最后一行，您输入了print "Game over. Your secret number was: " + mid. 但是，mid是一个数字，将其添加到字符串中没有任何意义。您需要先将其转换为字符串。

有几种方法可以做到这一点。您可以将其更改为：

  • print "Game over. Your secret number was: " + str(mid)
    ...mid变成一个字符串
  • print "Game over. Your secret number was: ", mid
    ...这样 Python 会将字符串 和mid视为两个变量，并自动在它们之间添加一个空格

.

low = 0
mid = 50
high = 100
secretnum = "Is your secret number " + str(mid) + "?"
print"Please think of a number between 0 and 100!"
print secretnum
herp = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. ")
while herp != 'c':
    if herp == 'h':
        high = mid
        mid = int((mid + low)/2)
    elif herp == 'l':
        low = mid
        mid = int((mid + high)/2)
    else:
        print"Sorry, I did not understand your input."
    print secretnum
    herp = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. ")
if herp == 'c':
    print "Game over. Your secret number was: " + str(mid)
于 2013-02-13T01:43:16.223 回答
0

当我构建我的代码时，我一开始遇到了同样的问题。查看您的代码后，我注意到一些错误，我将在此处突出显示它们：

  1. 您没有使用 raw_input 向用户询问号码
  2. 你不应该在你的时候使用'c'参数

  3. 您的 while 应该出现在 raw_input 问题之后

    num = raw_input("请想一个 0 到 100 之间的数字！")

    while mid != num:
    print ( "Is your secret number " + str(mid) + "?")
    herp = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. ")

在这里看到这个，你使用 while 所以它运行直到 mid 与用户选择的数字不同，打印它们非常重要，否则在你选择后你将无法看到程序的新猜测第一次猜测太低或太高。

  1. 无需一遍又一遍地重复“mid = int(low + high)/2”，只需在 else 之后使用它，每次 while 循环运行时，它都会改变 mid 的值。
  2. 您需要以字母“c”开始 if/elif/else 代码

  3. 您可以删除“print secretnum”行和之后的行

    如果 herp == 'c'：

            break
    elif herp == 'l':
        low = mid

    elif herp == 'h':
        high = mid

    else:
        print"Sorry, I did not understand your input."
    mid = int(low + high)/2
print "Game over. Your secret number was: " + str(mid)

    请注意，我使用“break”来离开 while 循环，因此消息 Game over。你的密码是：" + str(mid) 被打印出来。

最终结果应如下所示：

low = 0
high = 100
mid = (high + low)/2

num = raw_input("Please think of a number between 0 and 100!")

while mid != num:
    print ( "Is your secret number " + str(mid) + "?")
    herp = raw_input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. ")

    if herp == 'c':
        break
    elif herp == 'l':
        low = mid
        #mid = int(mid + high)/2
    elif herp == 'h':
        high = mid
        #mid = int(mid + low)/2
    else:
        print"Sorry, I did not understand your input."
    mid = int(low + high)/2
print "Game over. Your secret number was: " + str(mid)
于 2013-02-16T02:47:32.400 回答
0

试试下面的代码...

max_num=100
min_num=0
guess = int(abs(max_num/2))
print("Please think of a number between 0 and 100!")
for i in range(min_num,max_num):
  text = "Is your secret number "+str(guess)+"?\nEnter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. "
  xx = raw_input(text)
  if(xx == 'h'):
    max_num = guess
    guess = int((guess + min_num)/2)
  elif(xx == 'l'):
    min_num = guess
    guess = int((guess + max_num)/2)
  elif(xx == 'c'):
    print("Game over. Your secret number was:"+str(guess))
  else:  
    print("Sorry, I did not understand your input.")
    xx = str(input(text))
于 2016-09-16T09:53:28.043 回答
0

您不必包含int((mid + low)/2)在每个if-elif块下。这是同一练习的批准代码：

print("Please think of a number between 0 and 100!")
low = 0
high = 100
guess = (low + high) // 2

while True:
    print("Is your secret number " + str(guess) + "?")
    suggest = input("Enter 'h' to indicate the guess is too high. Enter 'l' to indicate the guess is too low. Enter 'c' to indicate I guessed correctly. ")
    if suggest == 'l':
        low = guess
    elif suggest == 'h':
        high = guess
    elif suggest == 'c':
        print("Game over. Your secret number was: " + str(guess))
        break
    else:
        print("Sorry, I did not understand your input.")
    guess = (low + high) // 2
于 2019-02-12T09:05:09.957 回答