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我被困在我必须为家庭作业做的编程练习上。我已经非常接近完成它，但我只是不知道如何让程序在最后要求用户“输入下一组限制”，而无需程序将新输入添加到旧输入中。

这是我书中出现的问题：

编写一个请求整数下限和上限的程序，计算从下限平方到上限平方的所有整数平方和，并显示答案。然后程序应继续提示限制并显示答案，直到用户输入等于或小于下限的上限。示例运行应如下所示：

Enter lower and upper integer limits: 5 9
The sums of the squares from 25 to 81 is 255
Enter next set of limits: 3 25
The sums of the squares from 9 to 625 is 5520
Enter next set of limits: 5 5
Done

这是我写的代码：

#include <stdio.h>

int main(void)
{
    int index, lower, upper, square, total, input;

    printf("Enter lower and upper integer limits: ");

    for (input = scanf("%d %d", &lower, &upper); input == 2; printf("Enter the next set of limits: \n"), scanf("%d %d", &lower, &upper))
    {
        for (index = lower; index <= upper; index++)
        {
            square = index * index;
            total += square;
        }
        printf("The sums of the squares from %d to %d is %d\n", lower * lower, upper * upper, total);
    }

    return 0;
}

任何帮助将非常感激！我已经为此工作了一个多小时。

更新，这就是我现在所拥有的，但它仍然不正确，因为当上限和下限相同时它不会打印出“完成”：

包括

int main(void) { int index, lower, upper, square, total;

printf("Enter lower and upper integer limits: ");

while (scanf("%d %d", &lower, &upper) == 2)
{
    total = 0;
    for (index = lower; upper > index; index++)
    {
        square = index * index;
        total += square;
    }
    printf("The sums of the squares from %d to %d is %d\n", lower * lower, upper * upper, total);
    printf("Enter the next set of limits: \n");
}


return 0;

}

更新* ****

感谢大家的帮助，我想我终于明白了：

包括

int main(void) { int index, lower, upper, square, total;

printf("Enter lower and upper integer limits: ");



while (scanf("%d %d", &lower, &upper) == 2)
{
    while (lower < upper)
    {
    total = 0;
    for (index = lower; index <= upper; index++)
    {
        square = index * index;
        total += square;
    }
        printf("The sums of the squares from %d to %d is %d\n", lower * lower, upper * upper, total);
        printf("Enter the next set of limits: \n");
        scanf("%d %d", &lower, &upper);

}
    printf("Done");
}

return 0;

}

4

3 回答 3

1

我真的很讨厌你的for循环。但这是一个问题。

只需total在循环内设置为零......无论如何你都应该这样做。目前它是未初始化的。

lower == upper不进行计算时应退出循环。有关我对您的for循环的想法，请参阅之前的注释。

也许是这样的：

printf("Enter lower and upper integer limits: ");
fflush(stdout);

while ( 2 == scanf("%d %d", &lower, &upper) && lower < upper )
{
    total = 0;

    // Do calculation and output result...

    printf("Enter the next set of limits: ");
    fflush(stdout);
}

printf("Done\n");
于 2013-02-12T22:11:10.297 回答
1 
int index, lower, upper, square, total, input;
while(1)
{
    total = 0;
    printf("Enter lower and upper integer limits: ");
    fflush(stdout);
    input = scanf("%d %d", &lower, &upper); 
    if(input != 2) continue;
    if(upper <= lower) break;
    for (index = lower; index <= upper; index++)
    {
        square = index * index;
        total += square;
    }
    printf("The sums of the squares from %d to %d is %d\n", lower , upper, total );
}
printf("Done\n");
于 2013-02-12T23:26:24.990 回答
0

只需将代码包装在：

while( upper > lower ) { 
...
}

（并进行适当的初始化upper，lower以便进入循环。）

于 2013-02-12T22:09:21.450 回答