python - Python使用re模块解析导入的文本文件

Question

def regexread():
    import re

    result = ''
    savefileagain = open('sliceeverfile3.txt','w')

    #text=open('emeverslicefile4.txt','r')
    text='09,11,14,34,44,10,11,  27886637,    0\n561, Tue, 5,Feb,2013, 06,25,31,40,45,06,07,  19070109,    0\n560, Fri, 1,Feb,2013, 05,21,34,37,38,01,06,  13063500,    0\n559, Tue,29,Jan,2013,'

    pattern='\d\d,\d\d,\d\d,\d\d,\d\d,\d\d,\d\d'
    #with open('emeverslicefile4.txt') as text:     
    f = re.findall(pattern,text)

    for item in f:
        print(item)

    savefileagain.write(item)
    #savefileagain.close()

上面写的函数解析文本并返回七个数字的集合。我有三个问题。

1. 首先，包含与 text='09,...etc' 完全相同的文本的“读取”文件返回 a TypeError expected string or buffer，即使阅读一些帖子我也无法解决。
2. 其次，当我尝试将结果写入“写入”文件时，没有返回任何内容，并且
3. 第三，我不确定如何获得与 print 语句相同的输出，即三行七个数字，每行是我想要的输出。

这是我第一次使用正则表达式，所以请温柔！

Answer 1

这应该可以解决问题，检查评论以了解我在这里做什么=）祝你好运

import re
filename = 'sliceeverfile3.txt'
pattern  = '\d\d,\d\d,\d\d,\d\d,\d\d,\d\d,\d\d'
new_file = []

# Make sure file gets closed after being iterated
with open(filename, 'r') as f:
   # Read the file contents and generate a list with each line
   lines = f.readlines()

# Iterate each line
for line in lines:

    # Regex applied to each line 
    match = re.search(pattern, line)
    if match:
        # Make sure to add \n to display correctly when we write it back
        new_line = match.group() + '\n'
        print new_line
        new_file.append(new_line)

with open(filename, 'w') as f:
     # go to start of file
     f.seek(0)
     # actually write the lines
     f.writelines(new_file)

Answer 2

你在正确的轨道上......

您将遍历文件： How to iterate over the file in python

并将正则表达式应用于每一行。当您意识到您正在尝试编写“项目”时，上面的链接应该真正回答您的所有 3 个问题，该项目在该循环之外不存在。