-2

我已经看到了很多关于这个主题的答案，但我不想使用 find. 我已经写了这个，但有些东西不起作用：

function CountEx()
{
    count=0
    for file in `ls $1`
    do
        echo "file is $file"
        if [ -x $file ]
        then
            count=`expr $count + 1`
        fi
    done
    echo "The number of executable files in this dir is: $count"
}
while getopts x:d:c:h opt
do
    case $opt in
        x)CountEx $OPTARG;;
        d)CountDir $OPTARG;;
        c)Comp $OPTARG;;
        h)help;;
        *)echo "Please Use The -h Option to see help"
        break;;
    esac
done

我正在使用这个脚本，如下所示：

yaser.sh -x './..../...../.....'

shell 运行它，然后它输出： The number of executable files in this dir is: 0 当此目录中有许多可执行文件时。

4

2 回答 2

0

If your goal is to count directories, there are so many options.

The find way, which you said you don't want:

CountDir() {
  if [[ ! -d "$1" ]]; then
    echo "ERROR: $1 is not a directory." >&2
    return 1
  fi
  printf "Total: %d\n" $(find "$1" -depth 1 -type d | wc -l)
}

The for way, similar to your example:

CountDir() {
  if [[ ! -d "$1" ]]; then
    echo "ERROR: $1 is not a directory." >&2
    return 1
  fi
  count=0
  for dir in "$1"/*; do
    if [[ -d "$dir" ]]; then
      ((count++))
    fi
  done
  echo "Total: $count"
}

The set way, which skips the loop entirely.

CountDir() {
  if [[ ! -d "$1" ]]; then
    echo "ERROR: $1 is not a directory." >&2
    return 1
  fi
  set -- "$1"/*/
  echo "Total: $#"
}
于 2013-02-12T12:35:54.920 回答
0

计算可执行文件的数量（如标题所示）

 count=0 
 for file in yourdir/*; do 
     if [ -x $file ]; then 
         count=$((count+1)); 
     fi; 
 done; 
 echo "total ${count}"

要计算文件夹，只需将-x测试更改为-d

于 2013-02-12T12:42:06.300 回答