1

嗨，我想简单地添加 1、2、3、4、5、6、7、8、9、10 等级。

我的输出现在给出以下内容：

USER ID | SCORE
2       | 10242
13231   | 3427
23732   | 3378
24638   | 2934
23468   | 1898

我试图实现的是：

RANK | USER ID | SCORE
#1   | 2       | 10242
#2   | 13231   | 3427
#3   | 23732   | 3378
#4   | 24638   | 2934
#5   | 23468   | 1898

这是我的 php：

<?php $result = mysql_query("SELECT * FROM `users_score` ORDER BY `users_score`.`score` DESC LIMIT 0 , 10") or die(mysql_error());
if(mysql_num_rows($result) > 0): ?>
<table>
    <tr>
        <th style="text-align:left;">ID</th>
        <th style="text-align:left;">SCORE</th>
    <tr>
    <?php while($row = mysql_fetch_assoc($result)): ?>
    <tr>
        <td><?php echo $row['user_id']; ?></td>
        <td style="font-weight: bold; color: #008AFF;"><?php echo $row['score']; ?></td>
    </tr>
    <?php endwhile; ?>
</table>
<?php endif; ?>

是否有一个简单的类似计数功能？

4

4 回答 4

1

您可以使用变量在查询中执行此操作。

SELECT  @row:=@row+1 as RankNo,
        a.UserID,
        a.Score
FROM    tableName a, (SELECT @row:=0) b
ORDER   BY a.Score DESC

但它有一个缺点，它不处理平局分数

如果要添加#排名，请连接RankNo with#`

更新 1

SELECT  CONCAT('#', @row:=@row+1) as RankNo,
        a.UserID,
        a.Score
FROM    tableName a, (SELECT @row:=0) b
ORDER   BY a.Score DESC
于 2013-02-12T12:04:01.370 回答
1 
SELECT (@rank := @rank + 1) AS rank, user_id, score
FROM (  SELECT user_id, score
        FROM scores, (SELECT @rank := 0) AS vars
        ORDER BY score DESC) AS h

SQLFiddle

于 2013-02-12T12:04:37.920 回答
0

您正在寻找的是等同于 MS SQL 的 row_number() 函数。之前已经回答过这个问题，例如这里或这里

答案是使用类似的东西：

SELECT @rn:=@rn+1 as RANK, ID, SCORE
       FROM `users_score`, (SELECT @rn:=0) as rn
       ORDER BY `users_score`.`score` DESC LIMIT 0

更新

只是出于兴趣，可以在 SQL 中处理匹配分数：

SELECT  @rn := @rn + case (@ls-SCORE) when 0 then 0 else @s end as RANK,
        ID,
        SCORE,
        @s := case (@ls-SCORE) when 0 then @s+1 else 1 end as STEPSIZE,
        @ls := SCORE as LASTSCORE
FROM    `users_score`.`score` a,
        (SELECT @rn := 0) b,
        (SELECT @ls := max(SCORE)+1 FROM `users_score`.`score`) c,
        (SELECT @s := 1) d
ORDER   BY a.Score DESC LIMIT 0

但是，如果您想这样做，那么在 PHP 代码中会更容易。

于 2013-02-12T12:17:39.687 回答
0 
If you just want changes in your php here is the code...

<?php 
$result = mysql_query("SELECT * FROM `users_score` ORDER BY `users_score`.`score` DESC LIMIT 0 ,10")  or die(mysql_error());

$rank=0;
$temp_score=0;

if(mysql_num_rows($result) > 0): ?>
<table>
    <tr>
        <th style="text-align:left;">RANK</th>
        <th style="text-align:left;">ID</th>
        <th style="text-align:left;">SCORE</th>
    <tr>
    <?php while($row = mysql_fetch_assoc($result)): 
         if($temp_score!=$row['score'])
             $rank++;
    ?>
    <tr>
     <td><?php echo "#".$rank; ?></td>
     <td><?php echo $row['user_id']; ?></td>
     <td style="font-weight: bold; color: #008AFF;"><?php echo $row['score']; ?></td>
    </tr>
    <?php 
         $temp_score=$row['score];
      endwhile; ?>
</table>
<?php endif; ?>
于 2013-02-12T12:25:45.497 回答