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我想在UIPopoverArrowDirectionLeft. 如何在单击按钮时将图像显示为弹出窗口?

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3 回答 3

1

我假设您的意思是会打开一个弹出屏幕,其中包含一个图像。这是如何做到的,只需以编程方式将图像添加到弹出视图,或者更好的是,直接在界面生成器中将图像添加到 MyPopOverView XIB

- (IBAction)showPopover:(id)sender
{
    if(![popoverController isPopoverVisible]) {
    myPopOver = [[MyPopOverView alloc] initWithNibName:@"MyPopOverView" bundle:nil];
    popoverController = [[UIPopoverController alloc] initWithContentViewController:myPopOver] ;

     // THE IMAGE
    UIImageView *icon = [[UIImageView alloc] initWithImage:[UIImage   imageNamed:@"popoverImage.png"]];

    [popoverController addsubview:icon];

    [popoverController setPopoverContentSize:CGSizeMake(350.0f, 500.0f)];
    [popoverController presentPopoverFromBarButtonItem:sender permittedArrowDirections:UIPopoverArrowDirectionAny animated:YES];

    } else {
        [popoverController dismissPopoverAnimated:YES];
    }
}
于 2013-02-12T10:00:22.417 回答
0

实现此场景的另一种方法是根据您的需求制作自定义 uiview,并在其中设置要显示为弹出框的图像。并在您想要显示弹出框时显示它。

于 2014-03-12T07:23:35.877 回答
0

像 WEPopOverController 一样使用自定义 popOverViewController。它包含一些属性来更改弹出箭头图像等。

http://www.cocoacontrols.com/controls/wepopover

- (WEPopoverContainerViewProperties *)defaultContainerViewProperties {
    WEPopoverContainerViewProperties *ret = [[WEPopoverContainerViewProperties new] autorelease];

    CGSize imageSize = CGSizeMake(30.0f, 30.0f);
    NSString *bgImageName = @"tri123.png";//@"round-rect-box.png";
    CGFloat bgMargin = 2.0;
    CGFloat contentMargin = 2.0;

    ret.leftBgMargin = bgMargin;
    ret.rightBgMargin = bgMargin;
    ret.topBgMargin = bgMargin;
    ret.bottomBgMargin = bgMargin;
    ret.leftBgCapSize = imageSize.width/2;
    ret.topBgCapSize = imageSize.height/2;
    ret.bgImageName = bgImageName;
    ret.leftContentMargin = contentMargin;
    ret.rightContentMargin = contentMargin;
    ret.topContentMargin = contentMargin;
    ret.bottomContentMargin = contentMargin;
    ret.arrowMargin = 1.0;
    ret.upArrowImageName = @"popoverArrowUpSimple.png";
    ret.downArrowImageName = @"tri2.png";   // Customize your Image
    ret.leftArrowImageName = @"popoverArrowLeftSimple.png";
    ret.rightArrowImageName = @"popoverArrowRightSimple.png";
    return ret;
}
于 2013-02-12T10:57:00.343 回答