我有两张这样的桌子
profile_answers
+---------+------------+
| id | class_name |
+---------+------------+
| 1 | Class 1 |
| 2 | Class 2 |
| 3 | Class 1 |
+---------+------------+
教育
+---------+--------------------+------------+
| id | profile_answers_id | sample |
+---------+--------------------+------------+
| 1 | 1 | 1234 |
| 2 | 1 | 2334 |
| 3 | 1 | 3434 |
+---------+------------+--------------------+
我运行了查询,
select educations.profile_answer_id, GROUP_CONCAT(educations.sample) from educations
LEFT JOIN profile_answers ON educations.profile_answers_id = profile_answers.id
我有
+--------+--------------------+-------------+
| id | sample |
+---------+--------------------+------------+
| 1 | 1234,2334,3434 |
+---------+------------+--------------------+
其实我想要
+--------+--------------------+-------------+
| id | sample |
+---------+--------------------+------------+
| 1 | 1234,2334,3434 |
| 2 | NULL |
| 3 | NULL |
+---------+------------+--------------------+
我尝试了 ISNULL、IFNULL 的组合,group_by profile_answers.id
它们给了我正确的结果,但结果证明它在运行时间方面非常昂贵