-1

因此，我已经为此苦苦挣扎了两天，但并没有取得很大的成功。

我得到的是由网页生成的 http POST，该网页被发送到我正在服务器上创建的 php 文件。所以基本上我正在尝试创建一个 php 侦听器脚本，当发生 http 帖子时，它将运行脚本将 xml 数据保存到 SimpleXMLElement 中，以便我可以编写一个 MYSQL 查询将数据导入我们的数据库。一旦我将数据放入 SimpleXMLElement，我就可以从那里接管，我遇到的问题是我无法让 listener.php 文件监听 HTTP POST 并将数据读入本地文件。

<?php
public void RunServer()
{
    var prefix = "http://*:4333/";
    HttpListener listener = new HttpListener();
listener.Prefixes.Add(prefix);
try
{
    listener.Start();
}
catch (HttpListenerException hlex)
{
    return;
}
while (listener.IsListening)
{
    var context = listener.GetContext();
    ProcessRequest(context);
}
listener.Close();
}

private void ProcessRequest(HttpListenerContext context) 
{
// Get the data from the HTTP stream
var body = new StreamReader(context.Request.InputStream).ReadToEnd();
$data = body
byte[] b = Encoding.UTF8.GetBytes("ACK");
context.Response.StatusCode = 200;
context.Response.KeepAlive = false;
context.Response.ContentLength64 = b.Length;

var output = context.Response.OutputStream;
output.Write(b, 0, b.Length);
context.Response.Close();
}
?>

This code is the closest I've gotten to what I need and I get a 500 error when I try to access the page. I'm not going to lie I'm pretty new to php and am having issues understanding function definitions. (Also I did get this code from a StackOverflow ticket that was closed)

I'm currently using php5 and apache on my server for my web hosting. ] I have a php.info() file setup and can post it if need be.

4

1 回答 1

1

If you want to save data into a SimpleXMLElement that will do it:

<?php
$xml = new SimpleXMLElement($_POST['xml-value-field']);
//insert into mysql db...
//write to local file...
?>
于 2013-02-11T17:39:53.363 回答