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我正在尝试创建将数字输入标签的键盘界面。沿着输入 4 位数密码的小键盘进行思考会更容易，就像打开锁定的 iOS 设备时一样。

我有四个标签，一旦输入就会显示数字。我有 12 个包含数字的按钮（加上一个取消和删除按钮）。每个按钮都有一个分配给它的标签。单击按钮时，我希望将该标签作为文本输入到下一个空标签。

我需要做的是在 setPin 函数中引用下一个空标签。我是不是走错了路，还是我错过了一点？我的代码的精简版本如下。

- (void)viewDidLoad
{
    [super viewDidLoad];

    [[self view] setBackgroundColor:[UIColor whiteColor]];
    [self setCurrField:1];

    // BUILD A VIEW TO CONTAIN THE LOGIN PANEL
    UIView *pinView = [[UIView alloc] initWithFrame:CGRectMake(10, 10, 400, 500)];
    pinView.backgroundColor = [UIColor lightGrayColor];

    // CREATE BUTTONS
    int nPos = 1;
    int leftPos;
    int topPos = 134;

    while (nPos <= 12) 
    {
        leftPos = (nPos%3 == 1) ? 19 : leftPos + 113 + 12;
        topPos = (nPos%3 == 1) ? topPos + 61 + 10 : topPos;

        // BUILD THE BUTTONS AND ADD TO THE PAGE
        UIButton *btn = [UIButton buttonWithType:UIButtonTypeCustom];
        [btn setTag:nPos];
        [btn addTarget:self action:@selector(setPin:) forControlEvents:UIControlEventTouchUpInside];
        [btn setFrame:CGRectMake(leftPos, topPos, 113, 61)];
        [btn setBackgroundColor: [UIColor darkGrayColor]];

        NSString *btnLabel;
        if(nPos <= 9)
        {
            btnLabel = [NSString stringWithFormat:@"%i", nPos];
        }
        else
        {
            switch (nPos) {
                case 10:
                    btnLabel = @"Cancel";
                    break;

                case 11:
                    btnLabel = @"0";
                    break;

                case 12:
                    btnLabel = @"Delete";
                    break;

                default:
                    break;
            }
        }
        [btn setTitle: btnLabel forState:UIControlStateNormal];

        [pinView addSubview:btn];

        nPos++;
    }

    // CREATE THE TEXTBOXES
    UILabel *char1Label = [[UILabel alloc] initWithFrame:CGRectMake(19, 65, 83, 91)];
    UILabel *char2Label = [[UILabel alloc] initWithFrame:CGRectMake(113, 65, 83, 91)];
    UILabel *char3Label = [[UILabel alloc] initWithFrame:CGRectMake(207, 65, 83, 91)];
    UILabel *char4Label = [[UILabel alloc] initWithFrame:CGRectMake(301, 65, 83, 91)];

    [pinView addSubview:char1Label];
    [pinView addSubview:char2Label];
    [pinView addSubview:char3Label];
    [pinView addSubview:char4Label];

    [[self view] addSubview:pinView];

}

-(void)setPin:(UIButton *)sender
{
    if(sender.tag <= 9 || sender.tag == 11)
    {
        [--charLabel[self currField]Label-- setText:[sender tag]];
        [self currField++];
    }
    elseif(sender.tag == 12) 
    {
        [self currField--];
        [--charLabel[self currField]Label-- setText:@""];
    }
}
4

2 回答 2

1

您需要保留对 textLabels 的引用，可能作为您所在类的属性。

@property (nonatomic) NSArray* textLabels; // Choose a more descriptive name than this

...

self.textLabels = @[ char1Label, char2Label, char3Label, char4Label ];


...

- (UILabel*) nextEmptyLabel {

    for (UILabel* label in self.TextLabels) 
    {
         NSString* trimmedText = [label.text stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]];
         if ([trimmedText length] == 0) {
             return label;
         }
    }

    return nil;  // No non empty label found
}
于 2013-02-11T16:35:39.047 回答
0

一种方法是将每个标签放入 NSMutableArray 中（以及您的视图中）。然后要获取每个标签，setPin您可以执行以下操作：

UILabel *label = [labelArray objectAtIndex:currField];
[label setText:[NSString stringWithFormat:@"%i", sender.tag]];
currField++;
于 2013-02-11T16:34:47.587 回答